Answer:
396
Step-by-step explanation:
Let AB extended intersect DC extended at point E
<span>We now have right triangle BEC with E = 90 degrees </span>
<span>For triangle BEC: </span>
<span>Exterior angle at E = 90 </span>
<span>Exterior angle at C = 148 (given) </span>
<span>Exterior angle of all polygons add up to 360 degrees </span>
<span>Exterior angle at B = 360−148−90 = 122 </span>
<span>So in quadrilateral ABCD </span>
<span>B = 122 </span>
<span>D = 360−44−148−122 = 46</span>
3x+7-5x=8
-2x+7=8
-2x=1
X=-1/2
y=3(-1/2)+7
y=-1.5+7
y=5.5
Answer:
-11
Step-by-step explanation:
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