Well I don't know.
Let's you and me get together and figure it out.
You said that . . . . . . . . . . . . . . 3t + 19 = 6
Subtract 19 from each side . . . 3t = -13
Divide each side by 3 . . . . . . . t = -13/3
Did I go too fast for you ?
Answer:
The total cost is 1.25 dollars.
Step-by-step explanation:
The reaction between HCl and CaCO₃ is giving by:
2HCl(aq) + CaCO₃(s) → CaCl₂(aq) + CO₂(g) + H₂O(l) (1)
0.500L M: 100.01g/mol
0.400M
According to equation (1), 2 moles of HCl react with 1 mol of CaCO₃, so to neutralize HCl, we need the next amount of CaCO₃:
The CaCO₃ mass of each tablet is:

Hence, the number of tablets that we need to neutralize the HCl is:
Finally, if every 80 tablets costs 4.00 dollars, 25 tablets will cost:

<u>So, the total cost to neutralize the HCl is 1.25 dollars.</u>
I hope it helps you!
The required probability of giving class period run between 51.5 and 51.75 is 0.125.
The lengths of her classes are uniformly distributed between 50 and 52 minutes.
<h3>What is the probability?</h3>
Probability, can be define as the ratio of favorable events to the n number of total events.
since,

p(r) = 0.125
Thus, the required probability of class period runs between 51.5 and 51.75 is given by 0.125
Learn more about probability here:
brainly.com/question/14290572
#SPJ1
It can be or it depends on how the equation is set up