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frutty [35]
3 years ago
7

Hello can someone please help me with this.

Mathematics
1 answer:
Zolol [24]3 years ago
3 0

Answer:

if there is equivalent ratio cookies should be 48

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What is the value of the expression? Show all work.<br> -9 - 6 + 8 ÷ -4 * -2?
nadya68 [22]

Step-by-step explanation:

To do Order of Operations, we need to go with the order of the formula, PEMDAS.

P= Parenthesis

E= Exponents

M= Multiply (Whatever Comes First in Equation: M and D)

D= Divide

A= Addition (Whatever Comes First in Equation: A and S)

S= Subtraction

---------------------------------------------

So, we need to start with parenthesis, there aren't any, so we move on to Exponents.

There are no Exponents either, so we start with division, then multiplication.

(We always have to go left to right).

So,

-9 - 6 + <u>8 / -4</u> x -2

-9 - 6 + <u>-2 x -2</u>

-9 - 6 + 4

Our problem is:

-9 - 6 + 4

We do subtraction, then addition. (Left to Right)

<u>-9 - 6 </u>+ 4

<u>-15 + 4</u>

-11.

Therefore, the answer is -11.

(Corrected)

7 0
3 years ago
I really need help, please and thank you
Citrus2011 [14]
I think it’s (A) I’m not sure...sorry if it’s wrong
7 0
3 years ago
If 7x + 3 = 24, what is the value of 5 - 4x?
Iteru [2.4K]

Answer:

Step-by-step explanation:

7x + 3= 24

7x= 24-3

7x= 21

x= 21/7

x= 3

Then we have that

5-4x

5-4(3)

5-12

Answer= -7

3 0
2 years ago
Which expression is equivalent to ( 4mn / m^-2n^6)^-2a. n^6 / 16m^8b. n^10 / 16m^6c. n^10 / 8m^8d. 4m^3 / n^8?
Eva8 [605]

\huge{(} \small{\frac{4mn}{ {m}^{ - 2} {n}^{6}  }}  \huge{) } \small{{}^{  {}^{ {}^{ {}^{ - 2} } } } }\\  \\  \\ \huge{(} \small{   \frac{4 \times m {}^{1}  \times n {}^{1} }{ {m}^{ - 2} \times  {n}^{6}  }}  \huge{)} \small{^{  {}^{ {}^{ {}^{ - 2} } } }} \\  \\  \\  \huge{(} \small{4 \times  {m}^{1 - ( - 2)}  \times  {n}^{1 - 6}} \huge{)} \small{ {}^{  {}^{ {}^{ {}^{ - 2} } } } } \\  \\  \\   \huge{(} \small{ 4 \times  {m}^{1 + 2}  \times  {n}^{ - 5} } \huge{)} \small{ { }^{ {}^{  {}^{  {}^{ - 2} } }  } } \\  \\  \\ \small{  {(4)}^{ - 2} \times  ({m}^{3} ) ^{ - 2} \times  {(n{}^{ - 5} )}^{ - 2}    } \\  \\  \\  \frac{1}{ {4}^{2} }  \times  {m}^{ - 6}  \times  {n}^{ 10}  \\  \\  \\  \frac{1}{16}  \times  \frac{1}{ {m}^{6} }  \times  {n}^{10}  \\  \\  \\  \frac{ {n}^{10} }{16{m}^{6} }







\text{ Hence, option B is correct }
7 0
3 years ago
14 POINTS!
Katyanochek1 [597]
180 minutes to finish
8 0
3 years ago
Read 2 more answers
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