To factor quadratic equations of the form ax^2+bx+c=y, you must find two values, j and k, which satisfy two conditions.
jk=ac and j+k=b
The you replace the single linear term bx with jx and kx. Finally then you factor the first pair of terms and the second pair of terms. In this problem...
2k^2-5k-18=0
2k^2+4k-9k-18=0
2k(k+2)-9(k+2)=0
(2k-9)(k+2)=0
so k=-2 and 9/2
k=(-2, 4.5)
Answer:
√55x\11x⁸y⁵
Step-by-step explanation:
Factor the numerator and denominator and cancel the common factors.
use quizzes and type line plot and your question it helps alot
Answer:
2x^2-16x+34
Step-by-step explanation:
Since Y is equal to -5
And you substitute -5 in the equation.
You now have -5=2x^2-16x+29
Add 5 to both sides
5-5=2x^-16x+29+5
