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Jet001 [13]
2 years ago
14

Is (1, -7) a solution of y=x-8? Νο Yes

Mathematics
2 answers:
olchik [2.2K]2 years ago
6 0

hi die cry why guy shy fiy

aivan3 [116]2 years ago
4 0

Answer:

Yes

Step-by-step explanation:

You just plug in the values.  -7 = 1-8. You plug in 1 for x, and -7 for y

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Can somebody please help me
olasank [31]

Answer:

70

Step-by-step explanation:

Complementary angles equal 90 degrees

90 - 20 = 70

I hope this helps!

5 0
2 years ago
What is the slope of a line that is perpendicular to the line whose equation is 7x−3y=10?
Sonja [21]

Since this equation is already in standard form, there is no need to convert it. Standard form is Ax + By = C. In this equation, 7 = A, 3 = B, and 10 = C. From standard form, Ax + By = C equals negative A over B.

7x + 3y = 10

↓

\displaystyle\ m= \frac{-7}{-3}

Then you'd simplify.

\displaystyle\ m=\frac{7}{3}

The slope cannot be simplified any more, so this would be the final answer.

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<em>- Marlon Nunez</em>

7 0
2 years ago
Hello please help me solve this :) will give braisnlt
Serjik [45]
I wrote ones but I hope it’s right and helps

3 0
3 years ago
Read 2 more answers
Andre and Morgan are both headed to Florida for vacation. Andre will drive 70 miles per hour. Morgan will drive 55 miles per hou
babymother [125]

Answer:

The number of hours Moran wold have driven before Andre catches up with him is 14 hours

Step-by-step explanation:

The given information are;

The speed with which Andre will drive = 70 miles per hour

The speed with which Morgan will drive = 55 miles per hour

The time of departure of Morgan = 3 hours before Andre departs

Let the time at which Andre catches up with Morgan be, t

We have, from the definition of distance traveled;

Distance traveled =Speed × Time

The distance Morgan would have driven in t hours = 55 × t

Given that to catch up with Morgan, Andre has to travel the same distance, and that Andre starts 3 hours late, we have;

The distance Andre would  drive when Morgan has driven for t hours = 70 × (t - 3)

Therefore, since the distance at the point they meet is the same distance for them both, we have;

55 × t = 70 × (t - 3)

55 × t = 70 × t - 210

210 = 70 × t - 55 × t  = 15 × t

t = 210/15 = 14 hours

Therefore, Morgan would have driven for 14 hours before Andre catches uo with him.

4 0
3 years ago
What are the four points of intersection between 4x^2 + y^2 - 4y - 32 = 0 and x^2 - y - 7 = 0 ? Solve algebraically
tensa zangetsu [6.8K]
Remember (a²-b²)=(a-b)(a+b)

solve for  a single variable
solve for y in 2nd

add y to both sides
x²-7=y
sub (x²-7) for y in other equaiton

4x²+(x²-7)²-4(x²-7)-32=0
expand
4x²+x⁴-14x²+49-4x²+28-32=0
x⁴-14x²+45=0
factor
(x²-9)(x²-5)=0
(x-3)(x+3)(x-√5)(x+√5)=0
set each to zero

x-3=0
x=3

x+3=0
x=-3

x-√5=0
x=√5

x+√5=0
x=-√5


sub back to find y

(x²-7)=y

for x=3
9-7=2
(3,2)

for x=-3
9-7=2
(-3,2)

for √5
5-7=-2
(√5,-2)

for -√5
5-7=-2
(-√5,-2)


the intersection points are

(3,2)
(-3,2)
(√5,-2)
(-√5,-2)
8 0
3 years ago
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