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SpyIntel [72]
3 years ago
10

A walker and a cyclist are 45 miles apart. They move towards each other with speeds of 5 mph and 10 mph respectively. In how man

y hours will they meet?
Mathematics
1 answer:
Ymorist [56]3 years ago
4 0

Answer: they will meet after 3 hours.

Step-by-step explanation:

Let t represent the number of hours it will take them to meet.

A walker and a cyclist are 45 miles apart. If they move towards each other, in t hours, they would have covered a total of 45 miles

Distance = speed × time

They move towards each other with speeds of 5 mph and 10 mph respectively. It means that the distance covered by the walker in t hours is 5 × t = 5t

Also, the distance covered by the cyclist in t hours is 10 × t = 10t

Since the total distance covered us 45 miles, then

5t + 10t = 45

15t = 45

t = 45/15

t = 3 hours

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one number is equal to the square of another. find the numbers if both are positive and their sum is 1122
statuscvo [17]

Answer:

One number is 561

The other number is 23.6854

Step-by-step explanation:

x = y^2                One number = the square of another

x + y^2 = 1122     The sum of the two numbers is 1122

Substitute y^2 in for x on the second equation.

y^2 + y^2 = 1122    Combine like terms on the left

2y^2 = 1122            Divide by 2

y^2 = 1122/2

y^2 = 561                Take the square root of both sides.

y = 23.6854            

x = y^2

x = 561

y^2 = 561


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