1. 6 is the answer
2. 56 is divisible by 14
Answer:
Multiple answers
Step-by-step explanation:
The original urns have:
- Urn 1 = 2 red + 4 white = 6 chips
- Urn 2 = 3 red + 1 white = 4 chips
We take one chip from the first urn, so we have:
The probability of take a red one is :
(2 red from 6 chips(2/6=1/2))
For a white one is:
(4 white from 6 chips(4/6=(2/3))
Then we put this chip into the second urn:
We have two possible cases:
- First if the chip we got from the first urn was white. The urn 2 now has 3 red + 2 whites = 5 chips
- Second if the chip we got from the first urn was red. The urn two now has 4 red + 1 white = 5 chips
If we select a chip from the urn two:
- In the first case the probability of taking a white one is of:
= 40% ( 2 whites of 5 chips) - In the second case the probability of taking a white one is of:
= 20% ( 1 whites of 5 chips)
This problem is a dependent event because the final result depends of the first chip we got from the urn 1.
For the fist case we multiply :
x
=
= 26.66% (
the probability of taking a white chip from the urn 1,
the probability of taking a white chip from urn two)
For the second case we multiply:
x
=
= .06% (
the probability of taking a red chip from the urn 1,
the probability of taking a white chip from the urn two)
Answer:
<h2>20</h2>
<em>Solution</em><em>,</em>
<em><</em><em>N=</em><em>1</em><em>8</em><em>0</em><em>-</em><em>5</em><em>3</em><em>-</em><em>4</em><em>4</em>
<em> </em><em> </em><em> </em><em> </em><em>=</em><em>8</em><em>3</em>
<h3>
<em>Apply </em><em>sines </em><em>rule,</em></h3>
<em>
</em>
<em>hope </em><em>this </em><em>helps.</em><em>.</em>
<em>Good </em><em>luck</em><em> on</em><em> your</em><em> assignment</em><em>.</em><em>.</em>
Whole number
integer
natural number
rational
Answer:
E and A
Step-by-step explanation: