Answer:
The general rule for the nth term of this sequence will be:
Step-by-step explanation:
Given the sequence
12a, 15a, 18a, 21a, 24a,...
An arithmetic sequence has a constant difference 'd' and is defined by
Here,
a₁ = 12a
computing the differences of all the adjacent terms
d = 15a-12a = 3a, d = 18a-15a=3a, d=21a-18a=3a, d=24a-21a=3a
using the nth term formula
substituting a₁ = 12a, d = 3a
Therefore, the general rule for the nth term of this sequence will be:
Answer:
48
Step-by-step explanation:
First of all find the scale.
36/9=4
So now you do 4 x 12
48
<h2>(25) 7th Grade Swimmers</h2><h2>25:80</h2>
Each of those bones pictures are equal to 2 bones. The question is asking, how many more rib bones than skull and jaw bones combined, so you’re gonna have to do some addition and subtraction.
You take the number of skull bones, which is 1(2), and add that to the number of jaw bones, which is 0. Giving you a total of 2 bones.
Then you are taking the rib bones 3(2) and finding out that you have 6.
So with that information, you can find out that there are 4 more rib more than skull and jaw bones combines (6-2=4)
Ratio of girls = 7/10
So, no. of girls = 200 × 7/10 = 20×7 = 140
