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2 years ago

6

Which triangle is congruent to triangle PQR

1 answer:

alexgriva [62]2 years ago

4 0

Answer:

Triangular PQR is congruent to triangular ABC

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Round 8.41315 correct to 2 decimal places

Nadya [2.5K]

Answer:

8.41

Step-by-step explanation:

i think

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2 years ago

What is the area where if this figurine ?ixl question

nydimaria [60]

Answer:

The area of the figure is 97 square inches

Step-by-step explanation:

In the given figure

<em>To find the area of the figure we can find </em><em>the area of the big rectangle with dimensions 7 inches and 19 inches</em><em> and subtract from it </em><em>the area of the small rectangle with dimensions 4 inches and 9 inches</em>

∵ The area o the rectangle = length × width

∵ The dimensions of the big rectangle are 7 inches and 19 inches

∴ The width = 7 inches

∴ The length = 19 inches

→ Substitute them in the rule of the area above

∵ The area of the big rectangle = 19 × 7

∴ The area of the big rectangle = 133 inches²

∵ The dimensions of the small rectangle are 4 inches and 9 inches

∴ The width = 4 inches

∴ The length = 9 inches

→ Substitute them in the rule of the area above

∵ The area of the small rectangle = 9 × 4

∴ The area of the small rectangle = 36 inches²

→ Subtract the area of the small rectangle from the area of the big

rectangle to get the area of the green figure

∵ The area of the figure = the big area - the small area

∴ The area of the figure = 133 - 36

∴ The area of the figure = 97 inches²

∴ The area of the figure is 97 square inches

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3 years ago

The lakeside tour bus traveled 490 miles on saturday and 225 miles on sunday. About how many more miles did it travel on saturda

Monica [59]

490-225=265
Is the answer

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3 years ago

Read 2 more answers

If carol hangs a picture using 3/8 yard of a wire that is 1 1/8 yards long.how much wire will carol have left?

Artemon [7]

Let the wire left be x yards.

Therefore, the answer of your question will be x yards.

Answer = x yards

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2 years ago

1. an alloy contains zinc and copper in the ratio of 7:9 find weight of copper of it had 31.5 kgs of zinc.

m_a_m_a [10]

Answer:

Step-by-step explanation:

Question (1). An alloy contains zinc and copper in the ratio of 7 : 9.

If the weight of an alloy = x kgs

Then weight of copper = $\frac{9}{7+9}\times (x)$

= $\frac{9}{16}\times (x)$

And the weight of zinc = $\frac{7}{7+9}\times (x)$

= $\frac{7}{16}\times (x)$

If the weight of zinc = 31.5 kg

31.5 = $\frac{7}{16}\times (x)$

x = $\frac{16\times 31.5}{7}$

x = 72 kgs

Therefore, weight of copper = $\frac{9}{16}\times (72)$

= 40.5 kgs

2). i). 2 : 3 = $\frac{2}{3}$

4 : 5 = $\frac{4}{5}$

Now we will equalize the denominators of each fraction to compare the ratios.

$\frac{2}{3}\times \frac{5}{5}$ = $\frac{10}{15}$

$\frac{4}{5}\times \frac{3}{3}=\frac{12}{15}$

Since, $\frac{12}{15}>\frac{10}{15}$

Therefore, 4 : 5 > 2 : 3

ii). 11 : 19 = $\frac{11}{19}$

19 : 21 = $\frac{19}{21}$

By equalizing denominators of the given fractions,

$\frac{11}{19}\times \frac{21}{21}=\frac{231}{399}$

And $\frac{19}{21}\times \frac{19}{19}=\frac{361}{399}$

Since, $\frac{361}{399}>\frac{231}{399}$

Therefore, 19 : 21 > 11 : 19

iii). $\frac{1}{2}:\frac{1}{3}=\frac{1}{2}\times \frac{3}{1}$

$=\frac{3}{2}$

$\frac{1}{3}:\frac{1}{4}=\frac{1}{3}\times \frac{4}{1}$

= $\frac{4}{3}$

Now we equalize the denominators of the fractions,

$\frac{3}{2}\times \frac{3}{3}=\frac{9}{6}$

And $\frac{4}{3}\times \frac{2}{2}=\frac{8}{6}$

Since $\frac{9}{6}>\frac{8}{6}$

Therefore, $\frac{1}{2}:\frac{1}{3}>\frac{1}{3}:\frac{1}{4}$ will be the answer.

IV). $1\frac{1}{5}:1\frac{1}{3}=\frac{6}{5}:\frac{4}{3}$

$=\frac{6}{5}\times \frac{3}{4}$

$=\frac{18}{20}$

$=\frac{9}{10}$

Similarly, $\frac{2}{5}:\frac{3}{2}=\frac{2}{5}\times \frac{2}{3}$

$=\frac{4}{15}$

By equalizing the denominators,

$\frac{9}{10}\times \frac{30}{30}=\frac{270}{300}$

Similarly, $\frac{4}{15}\times \frac{20}{20}=\frac{80}{300}$

Since $\frac{270}{300}>\frac{80}{300}$

Therefore, $1\frac{1}{5}:1\frac{1}{3}>\frac{2}{5}:\frac{3}{2}$

V). If a : b = 6 : 5

$\frac{a}{b}=\frac{6}{5}$

$=\frac{6}{5}\times \frac{2}{2}$

$=\frac{12}{10}$

And b : c = 10 : 9

$\frac{b}{c}=\frac{10}{9}$

Since a : b = 12 : 10

And b : c = 10 : 9

Since b = 10 is common in both the ratios,

Therefore, combined form of the ratios will be,

a : b : c = 12 : 10 : 9

7 0

3 years ago