<span>X^2+x-2/1-x^2 ÷ 2x^2-6x-20/x^2-4x-5
(x + 2)(x - 1) (x - 5)(x + 1)
= ------------------- * ---------------------
(1 + x)(1- x) 2(x + 2)(x - 5)
</span> (x - 1)
= ----------
2(1- x)
- (1 - x)
= -------------
2(1 - x)
= -1/2
answer
-1/2
Question:
Find the constant of proportionality k. Then write an equation for the relationship between x and y
Answer:
(a) 
(b) 
Step-by-step explanation:
Given
Solving (a): The constant of proportionality:
Pick any two corresponding x and y values
The constant of proportionality k is:
Solving (b): The equation
In (a), we have:
k can also be expressed as:
Substitute values for x1, y1 and k
Cross multiply:
Open bracket
Add 10 to both sides
Answer:
∠ EFH = 112°
Step-by-step explanation:
∠ ACD and ∠ EFH are Alternate exterior angles and are congruent, thus
11x - 20 = 9x + 4 ( subtract 9x from both sides )
2x - 20 = 4 ( add 20 to both sides )
2x = 24 ( divide both sides by 2 )
x = 12
Thus
∠ EFH = 11x - 20 = 11(12) - 20 = 132 - 20 = 112°
Answer:
B is the correct
Step-by-step explanation:
choose as brinliest
t/3 is your expression.
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