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4 years ago

8

A transcriptionist types 62 words per minute. Which statement is correct? As the number of words increases, the number of minute

s decreases. As the number of words decreases, the number of minutes increases. The number of words, w, is the dependent variable. The brand of keyboard causes a change in the number of words typed per minute.

2 answers:

JulsSmile [24]4 years ago

6 0

Answer:

The answer is D or the third one

Step-by-step explanation:

I took the test in Edge and got it right! :)

liubo4ka [24]4 years ago

5 0

Answer:

e

Step-by-step explanation:

e

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Answer:

3.5% of 20, (0.035)*20, and 7% of 10

Step-by-step explanation:

Converting the mixed number (3 1/2) to a decimal yields 3.5, so 3.5% of 20 is correct.

3 1/2 is not equal to 3 1/2%, so 3 1/2 * 20 is not correct.

Converting the percentage to a decimal yields .035 which makes .35 too large, so (0.35) * 20 is not correct.

Changing the percentage to a decimal yields .035, so (0.035) * 20 is correct.

If you divide 20 by 2, you get 10, and if you multiply 2 by 3 1/2, you get 7. The 2 remains part of the expression, so it is equal to 3 1/2 of 20.

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What number goes in the box?<br> 2 ^ ( ) = (2^7 ÷ 2^9)^3

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Step-by-step explanation:

$(\frac{2^{7}}{2^{9}})^{3} \\(\frac{128}{512})^{3} \\(\frac{1}{4})^{3}\\(\frac{1}{4})*(\frac{1}{4})*(\frac{1}{4})\\\frac{1*1*1}{4*4*4} \\\frac{1^{3} }{4^{3} } \\\frac{1}{64} \\2^{x}=\frac{1}{64}\\log 2^x=log\frac{1}{64}\\x*(log(2))=log\frac{1}{64}\\x=\frac{log\frac{1}{64}}{log(2)} \\x=-6$

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3 years ago

The vertices of quadrilateral E F G H are E (-7,3) , F (-4,6) , G (5, -3) , and H (2,-6). What kind of quadrilateral is E F G H?

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Step-by-step explanation:

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3 years ago

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Gelneren [198K]

Answer:

General equation of line : $y = mx+c$ --1

Where m is the slope or unit rate

Table 1)

p d

1 3

2 6

4 12

d = Number of dollars (i.e.y axis)

p = number of pound(i.e. x axis)

First find the slope

First calculate the slope of given points

$m = \frac{y_2-y_1}{x_2-x_1}$ ---A

$(x_1,y_1)=(1,3)$

$(x_2,y_2)=(2,6)$

Substitute values in A

$m = \frac{6-3}{2-1}$

$m = 3$

Thus the unit rate is 3 dollars per pound.

So, It matches the box 1 (Refer the attached figure)

Equation 1 : $p=3d$

$\frac{p}{3}=d$

Since p is the x coordinate and d is the y coordinate

On Comparing with 1

$m = \frac{1}{3}$

Thus the unit rate is $\frac{1}{3}$ dollars per pound

So, It matches the box 2 (Refer the attached figure)

Equation 2 : $\frac{1}{3}d=3p$

$d=9p$

Since p is the x coordinate and d is the y coordinate

On Comparing with 1

$m =9$

Thus the unit rate is 9 dollars per pound

So, It matches the box 3 (Refer the attached figure)

Table 2)

p d

1/9 1

1 9

2 18

d = Number of dollars (i.e.y axis)

p = number of pound(i.e. x axis)

$(x_1,y_1)=(\frac{1}{9},1)$

$(x_2,y_2)=(1,9)$

Substitute values in A

$m = \frac{9-1}{1-\frac{1}{9}}$

$m = \frac{8}{frac{8}{9}}$

$m = 9$

Thus the unit rate is 9 dollars per pound

So, It matches the box 3 (Refer the attached figure)

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