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3 years ago

Please help me because I don't understand how to do it.:)

Mathematics

1 answer:

Flura [38]3 years ago

8 0

Answer:

sqrt(37) is closest to 6

Step-by-step explanation:

We know 6 is a rational number

Square 6

6*6 = 36

Which of our numbers is closest to 36

Now take the square root of each

sqrt(37) is closest to sqrt(36)

sqrt(37) is closest to 6

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What? I don’t under stand

s2008m [1.1K]

Answer:

? = h

Step-by-step explanation:

v = lwh

v / wh = lwh / wh

v / wh = l

Hopefully this helped!

Brainliest please?

5 0

3 years ago

Read 2 more answers

What is the least common multiple of 8 and 9? Enter your answer in the box.

Contact [7]

Answer:

Step-by-step explanation:

The LCM is when you find the lowest factor that 2 or more numbers share.

For 8 and 9,you would just need to keep multiplying each other until you find the same numbers. It would look something like this.

8,16,24,32,40,48,56,64,72..... etc.

9,18,27,36,45,54,63,72,81..... etc.

You can see how they both have the same factor (72), and since that is the lowest factor (which means I can find a lower factor then 72) then your LCM of 8 and 9 should be 72 :)

4 0

3 years ago

Find the value of x that makes the equation true. x + 4 = 12

kirill115 [55]

x + 4 = 12 Subtract 4 on both sides to get "x" by itself

x + 4 - 4 = 12 - 4

x = 8

7 0

3 years ago

Area of a triangle with points at (-9,5), (6,10), and (2,-10)

Ann [662]

First we are going to draw the triangle using the given coordinates.
Next, we are going to use the distance formula to find the sides of our triangle.
Distance formula: $d= \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

Distance from point A to point B:
$d_{AB}= \sqrt{[6-(-9)]^2+(10-5)^2}$
$d_{AB}= \sqrt{(6+9)^2+(10-5)^2}$
$d_{AB}= \sqrt{(15)^2+(5)^2}$
$d_{AB}= \sqrt{225+25}$
$d_{AB}= \sqrt{250}$
$d_{AB}=15.81$

Distance from point A to point C:
$d_{AC}= \sqrt{[2-(-9)]^2+(-10-5)^2}$
$d_{AC}= \sqrt{(2+9)^2+(-10-5)^2}$
$d_{AC}= \sqrt{11^2+(-15)^2}$
$d_{AC}= \sqrt{121+225}$
$d_{AC}= \sqrt{346}$
$d_{AC}= 18.60$

Distance from point B from point C
$d_{BC}= \sqrt{(2-6)^2+(-10-10)^2}$
$d_{BC}= \sqrt{(-4)^2+(-20)^2}$
$d_{BC}= \sqrt{16+400}$
$d_{BC}= \sqrt{416}$
$d_{BC}=20.40$

Now, we are going to find the semi-perimeter of our triangle using the semi-perimeter formula:
$s= \frac{AB+AC+BC}{2}$
$s= \frac{15.81+18.60+20.40}{2}$
$s= \frac{54.81}{2}$
$s=27.41$

Finally, to find the area of our triangle, we are going to use Heron's formula:
$A= \sqrt{s(s-AB)(s-AC)(s-BC)}$
$A=\sqrt{27.41(27.41-15.81)(27.41-18.60)(27.41-20.40)}$
$A= \sqrt{27.41(11.6)(8.81)(7.01)}$
$A=140.13$

We can conclude that the perimeter of our triangle is 140.13 square units.

3 0

3 years ago

Can you guys figure this out please x6∙x∙x3= x6+3 = x9

Marat540 [252]

Answer:

Below.

Step-by-step explanation:

x^6 . x . x^3

= x^6 . x^1 . x^3

= x^(6+1+3)

= x^10.

5 0

3 years ago