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MrMuchimi
2 years ago
13

Caroline earns $49000 a year, and her friend Jennifer earns $51000 a year but doesn't belong to a health fund. The tax rule this

year is $40000 and above pay $5000 plus 40 cents in the dollar in tax on anything over $40000 per annum and $50000 and above pay $ 9000 plus 30 cents in the dollar in tax on anything over $ 50,000per annum, plus 2% of her income if he is not in a health fund.
Mathematics
1 answer:
Lina20 [59]2 years ago
5 0

Answer:

Caroline has to pay $8600 taxes

Jennifer has to pay $10320 taxes

Step-by-step explanation:

I guess the question is who has to pay how much taxes, right ?

Caroline earns $49000, and I guess, she belongs to a health fund.

she has to pay $5000 for the first $40000.

and for the remaining $9000 she has to pay $0.40 per dollar.

that means 9000×0.4 = $3600

and no penalties for no health fund.

so altogether $5000 + $3600 = $8600 taxes

Jennifer earns $51000 and did not belong to a health fund.

she has to pay $9000 for the first $50000.

and for the remaining $1000 she had to pay $0.30 part dollar.

that means 1000×0.3 = $300

and 2% of the total income because no health fund

51000×0.02 = $1020

so, altogether $9000+$300+$1020 = $10320 taxes

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3 questions in 1
MrRissso [65]

Answer:

1. D. 20, 30, and 50

2. A. 86

3. B. 94

Step-by-step explanation:

1. To find the outliers of the data set, we need to determine the Q1, Q3, and IQR.

The Q1 is the middle data in the lower part (first 10 data values) of the data set (while the Q3 is the middle data of the upper part (the last 10 data values) the data set.

Since it is an even data set, therefore, we would look for the average of the 2 middle values in each half of the data set.

Thus:

Q1 = (85 + 87)/2 = 86

Q3 = (93 + 95)/2 = 94

IQR = Q3 - Q1 = 94 - 86

IQR = 8

Outliers in the data set are data values below the lower limit or above the upper limit.

Let's find the lower and upper limit.

Lower limit = Q1 - 1.5(IQR) = 86 - 1.5(8) = 74

The data values below the lower limit (74) are 20, 30, and 50

Let's see if we have any data value above the upper limit.

Upper limit = Q3 + 1.5(IQR) = 94 + 1.5(8) = 106

No data value is above 106.

Therefore, the only outliers of the data set are:

D. 20, 30, and 50

2. See explanation on how to we found the Q1 of the given data set as explained earlier in question 1 above.

Thus:

Q1 = (85 + 87)/2 = 86

3. Q3 = (93 + 95)/2 = 94

3 0
2 years ago
What is the equation for a circle with a center at (-2,-4) that passes through the point (3,8)?
Margarita [4]
Check the picture below.

so, the center of the circle is the midpoint of that diametrical segment, and half that length is the radius.

\bf ~~~~~~~~~~~~\textit{middle point of 2 points }
\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
%  (a,b)
&&(~ -2 &,& -4~) 
%  (c,d)
&&(~ 3 &,& 8~)
\end{array}\qquad
%   coordinates of midpoint 
\left(\cfrac{ x_2 +  x_1}{2}\quad ,\quad \cfrac{ y_2 +  y_1}{2} \right)
\\\\\\
\left( \cfrac{3-2}{2}~~,~~\cfrac{8-4}{2} \right)\implies \left( \frac{1}{2}~,~2 \right)\impliedby center

\bf ~~~~~~~~~~~~\textit{distance between 2 points}
\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
%  (a,b)
&&(~ -2 &,& -4~) 
%  (c,d)
&&(~ 3 &,& 8~)
\end{array}~~~ 
%  distance value
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
d=\sqrt{[3-(-2)]^2+[8-(-4)]^2}\implies d=\sqrt{(3+2)^2+(8+4)^2}
\\\\\\
d=\sqrt{25+144}\implies d=\sqrt{169}\implies d=13\qquad\qquad \qquad  \stackrel{radius}{\frac{13}{2}}

\bf \textit{equation of a circle}\\\\ 
(x- h)^2+(y- k)^2= r^2
\qquad 
center~~(\stackrel{\frac{1}{2}}{ h},\stackrel{2}{ k})\qquad \qquad 
radius=\stackrel{\frac{13}{2}}{ r}
\\\\\\
\left( x-\frac{1}{2} \right)^2+(y-2)^2=\left( \frac{13}{2} \right)^2\implies \left( x-\frac{1}{2} \right)^2+(y-2)^2=\frac{169}{4}

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It's b 1/9 mile i thank

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John has all the marbles in the world. What percent of the worlds marbles does John have?
Eddi Din [679]

Answer:

100%

Step-by-step explanation:

All of them = 100%.

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3 years ago
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