Answer:
1). 183
2). 83
3). 353
4). -2652
5). 59
6). 510
7). -293
8). 79
9). 78
10). 87
Step-by-step explanation:
Considering order of operation, parenthesis must be simplified first.
The solutions to the given questions are shown below;
![1). \ \ 5+(7\times (3+2)^2) + 3=8 + (7\times (5)^2) = 8 + (7\times 25) = 8 + 175 = 183](https://tex.z-dn.net/?f=1%29.%20%5C%20%5C%205%2B%287%5Ctimes%20%283%2B2%29%5E2%29%20%2B%203%3D8%20%2B%20%20%287%5Ctimes%20%285%29%5E2%29%20%20%3D%208%20%2B%20%287%5Ctimes%2025%29%20%3D%208%20%2B%20175%20%3D%20183)
![2). \ 16+(8+ (6+2)^2) - 5=16-5 + (8+ (8)^2) = 11 + (8+64) = 11 + 72 = 83](https://tex.z-dn.net/?f=2%29.%20%5C%2016%2B%288%2B%20%286%2B2%29%5E2%29%20-%205%3D16-5%20%2B%20%20%288%2B%20%288%29%5E2%29%20%20%3D%2011%20%2B%20%288%2B64%29%20%3D%2011%20%2B%2072%20%3D%2083)
![3). \ (15+ 3)^2 + ((14+6)+3^2)= (18)^2 + ((20) + 9) = 324 + (29) = 353](https://tex.z-dn.net/?f=3%29.%20%5C%20%2815%2B%203%29%5E2%20%2B%20%28%2814%2B6%29%2B3%5E2%29%3D%20%2818%29%5E2%20%2B%20%28%2820%29%20%2B%209%29%20%3D%20324%20%2B%20%2829%29%20%3D%20353)
![4). \ ((11+ 2)-(24+2)^2)\times 2^2 = (13 - 676) \times 4 = (-663)\times 4 = -2652](https://tex.z-dn.net/?f=4%29.%20%5C%20%28%2811%2B%202%29-%2824%2B2%29%5E2%29%5Ctimes%202%5E2%20%3D%20%2813%20-%20676%29%20%5Ctimes%204%20%20%3D%20%28-663%29%5Ctimes%204%20%3D%20-2652)
![5). \ ((4+3)^2+ 6) -5+3^2= (49 + 6) - 5 + 9= (49+6+9) - 5 = 64-5 = 59](https://tex.z-dn.net/?f=5%29.%20%5C%20%28%284%2B3%29%5E2%2B%206%29%20-5%2B3%5E2%3D%20%2849%20%2B%206%29%20-%205%20%2B%209%3D%20%2849%2B6%2B9%29%20-%205%20%3D%2064-5%20%3D%2059)
![6). \ (20+ 2)^2 +((15+7)+2^2)= (484) + (22+ 4)= 484 + 26 =510](https://tex.z-dn.net/?f=6%29.%20%5C%20%2820%2B%202%29%5E2%20%2B%28%2815%2B7%29%2B2%5E2%29%3D%20%28484%29%20%2B%20%2822%2B%204%29%3D%20484%20%2B%2026%20%3D510)
![7). \ ((12 + 4)- (15+3)^2+ 5^2 = (16 - 324) + 25 = -318 + 25 = -293](https://tex.z-dn.net/?f=7%29.%20%5C%20%28%2812%20%2B%204%29-%20%2815%2B3%29%5E2%2B%205%5E2%20%3D%20%2816%20-%20%20324%29%20%2B%2025%20%3D%20-318%20%2B%2025%20%3D%20-293)
![8). \ (6^2+ (24+ 3+5^2)) - 3^2= (36 + (52)) - 9 = (88) - 9 = 79](https://tex.z-dn.net/?f=8%29.%20%5C%20%286%5E2%2B%20%2824%2B%203%2B5%5E2%29%29%20-%203%5E2%3D%20%2836%20%2B%20%2852%29%29%20-%209%20%3D%20%2888%29%20-%209%20%3D%2079)
![9). \ ((10-4)^2\times 2) + 2 + 2^2= ((6)^2 \times 2) + 2 + 4 = (36\times 2)+ 6 = 72 + 6 = 78](https://tex.z-dn.net/?f=9%29.%20%5C%20%28%2810-4%29%5E2%5Ctimes%202%29%20%2B%202%20%2B%202%5E2%3D%20%28%286%29%5E2%20%5Ctimes%202%29%20%2B%202%20%2B%204%20%3D%20%2836%5Ctimes%202%29%2B%206%20%3D%2072%20%2B%206%20%3D%2078)
![10). \ (7^2 + (16 + 8 + 2^2)) + 3^2 = (49 + 28) + 9 = 78 + 9 = 87](https://tex.z-dn.net/?f=10%29.%20%5C%20%287%5E2%20%2B%20%2816%20%2B%208%20%2B%202%5E2%29%29%20%2B%203%5E2%20%3D%20%2849%20%2B%2028%29%20%2B%209%20%3D%2078%20%2B%209%20%3D%2087)
I don’t know if that 2 and 1/4 or 21/4 so I’ll do both.
2 and 1/4 is = 9/4
21/4 is = 5 and 1/4
Rao is 5 years old. In two years he will be 7 and Pau will be 14. Now minus 2 by 7 and you get 5.
So baically
reresent
s=number of studne tickes bouthgt
a=number of adult tickets bought
300 tickest sold
total=300
a+s=300
value=rate times number of peple
student value=4s
adults value=10a
total value=1950
4s+10a=1950
a. system of equations are
s+a=300
4s+10a=1950
b. solve
s+a=300
4s+10a=1950
a+s=300
multiply by -4
-4s-4a=-1200
add to other eqaution
4s+10a=1950
<u>-4s-4a=-1200 + </u>
0s+6a=750
6a=750
divide 6
a=125
subsiute
s+a=300
s+125=300
subtract 125
s=175
a. s+a=300
4s+10a=1950
b. solution above
175 students
125 aduls
the first box put 21 the second one put 7 then the last one put 7