Area: 60
Explanation: we know the height of the square therefore we know all of its dimensions. We can multiply 3x2 to get the height, which is 6. And add 3 to 7 to get the length, which is 10.
The formula for area is <em>A=wl</em>
<em>A=6(10)</em>
<em>A=60</em>
The answer is =x^2 +x +1 +2/x-1
The answer is diameter: 32 in, area: 64 in²
The perimeter of a sector of a circle is:
P = 2r + l
l = r<span>θ
P = 2r + r</span>θ<span>
P = 32 in
32 = 2r + r</span><span>θ
</span>32 - 2r = r<span>θ
</span>θ = (32 - 2r)/r
θ = (2*16 - 2*r)/r
θ = 2(16 - r)/r<span>
Area of the sector of the circle is:
A = r</span>²/2 * θ
A = r²/2 * 2(16 - r)/r
A = r² * (16 - r)/r
A = r(16 - r)
A = 16r - r²
For the maximum area:
A' = 16 - 2r
A' = 0
16 - 2r = 0
16 = 2r
r = 8 in
The diameter (D) of the circle is twice of the radius:
D = 2r = 2 * 8 = 16 in
The maximum area is:
A = 16r - r²
r = 8 in
A = 16 * 8 - 8²
A = 128 - 64
A = 64 in²
Answer:
31
Step-by-step explanation:
Add all of the integers together then divide by 4 bc thats how many integers there are in order to get the mean.
The equation for the base is that of a circle, so the cross sections will have a leg of length equal to the vertical distance between its halves.
x² + y² = 16 ⇒ y = ±√(16 - x²)
⇒ length = √(16 - x²) - (-√(16 - x²)) = 2 √(16 - x²)
Cross sections with thickness ∆x have a volume of
1/2 length² ∆x = 1/2 (2 √(16 - x²))² ∆x = (32 - 2x²) ∆x
since they are isosceles triangles and so their bases and heights are equal.
Then the total volume would be (D)
