All categories

3 years ago

4 description of meteor showers

Chemistry

1 answer:

mel-nik [20]3 years ago

5 0

Answer:

A meteor shower are defined as the celestial event in which a meteor comes from one point in the sky and visible in night sky.

Meteors are also known as Shooting stars as they glow when enters in the Earth surface as glowing streaks, where tail point to the origin in the sky and face faces the Earth surface.

Meteor showers take place when meteoroids entering Earth's atmosphere.

Meteor showers can repeat themselves because it depends on the comet orbits which can take place at the same time each year.

You might be interested in

How many grams are in 1 mole of Pb3(PO4)4?

kvasek [131]

Answer:

In 1 mol of Pb₃(PO₄)₄ occupies 1001.48 grams

Explanation:

This compound is the lead (IV) phosphate.

Grams that occupy 1 mole, means the molar mass of the compound

Pb = 207.2 .3 = 621.6 g/m

P = 30.97 .4 = 123.88 g/m

O = (16 . 4) . 4 = 256 g/m

621.6 g/m + 123.88 g/m + 256 g/m = 1001.48 g/m

6 0

3 years ago

Read 2 more answers

A system gains 652 kJ of heat, resulting in a change in internal energy of the system equal to +241 kJ. How much work is done?

levacccp [35]

Answer:

-411 kj

Explanation:

We solve by using this formula

∆U = ∆Q + ∆W

This formula is the first law of thermodynamics

Change in internal energy U = +241

Heat gained by system Q = 652

Putting the value into the equation

+241 = 652 + W

Workdone = 241 - 652

Workdone = -411 kj

Since work done is negative it means that work was done by the system

3 0

3 years ago

AWhich of the following terms is NOT used to refer to white blood cells?

myrzilka [38]

Answer:

C. Platelet

Hope this helps!

5 0

2 years ago

Read 2 more answers

A wooden tool is found at an archaeological site. Estimate the age of the tool using the following information: A 100 gram sampl

lord [1]

Answer:

2578.99 years

Explanation:

Given that:

100 g of the wood is emitting 1120 β-particles per minute

Also,

1 g of the wood is emitting 11.20 β-particles per minute

Given, Decay rate = 15.3 % per minute per gram

So,

Concentration left can be calculated as:-

C left = $[A_t]=\frac{11.20\ per\ minute}{15.3\ per\ minute\ per\ gram}\times [A_0]= 0.7320[A_0]$

Where,

$[A_t]$ is the concentration at time t

$[A_0]$ is the initial concentration

Also, Half life of carbon-14 = 5730 years

$t_{1/2}=\frac {ln\ 2}{k}$

Where, k is rate constant

So,

$k=\frac {ln\ 2}{t_{1/2}}$

$k=\frac {ln\ 2}{5730}\ years^{-1}$

The rate constant, k = 0.000120968 year⁻¹

Time =?

Using integrated rate law for first order kinetics as:

$[A_t]=[A_0]e^{-kt}$

So,

$\frac {[A_t]}{[A_0]}=e^{-0.000120968\times t}$

$\frac {0.7320[A_0]}{[A_0]}=e^{-0.000120968\times t}$

$0.7320=e^{-0.000120968\times t}$

$ln\ 0.7320=-0.000120968\times t$

<u>t = 2578.99 years</u>

8 0

3 years ago

HELP

Semenov [28]

C, 0.746 mol Ag.

1 mol Ag = 6.022 x 1023 atoms of Ag -> 4.49 x 1023 atoms of Ag x 1mol Ag/6.022 x 1023 atoms -> 0.746 mol Ag

7 0

3 years ago

4 description of meteor showers​

4 description of meteor showers