The perimeter of a rectangular park is 2.6 miles. the length of the park is 0.8 miles. what is the width of the park

Colt1911 [192]

Answer:

She has 80 apples in all.

Step-by-step explanation:

24=30%

(24÷3)=(30÷3)%

8=10%

(8×10)=(10×10)%

80=100%

7 0

3 years ago

labwork [276]

The total area of the room is 37.6376 and the no. of cans required to paint the wall is 3 cans.

The measurement of two of the walls is 2.86 metres and 3.16 metre

Area of the two walls = 2(length x breadth)

Area = 2(2.86 x 3.16) = 18.0752 m²

The measurement of the other two walls is 2.86 metres and 3.42 metres

Area of the two walls = 2(length × breadth)

Area = 2(2.86 × 3.42) = 19.5624 m²

Total area = 18.0752 + 19.5624 = 37.6376 m²

If one can of paint can cover 15 m², the no. of cans required to paint the bedroom will be

No. of cans = Total area/Area covered by one can of paint

No. of cans = 37.6376/15 = 2.5091 = 3 cans (approx.)

3 0

1 year ago

krek1111 [17]

Answer:

$\displaystyle f'(x) = \bigg( \frac{1}{2\sqrt{x}} - \sqrt{x} \bigg)e^\big{-x}$

General Formulas and Concepts:

Algebra I

Terms/Coefficients

Calculus

Differentiation

Basic Power Rule:

Derivative Rule [Quotient Rule]: $\displaystyle \frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}$

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle f(x) = \frac{\sqrt{x}}{e^x}$

Step 2: Differentiate

Derivative Rule [Quotient Rule]: $\displaystyle f'(x) = \frac{(\sqrt{x})'e^x - \sqrt{x}(e^x)'}{(e^x)^2}$
Basic Power Rule: $\displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}(e^x)'}{(e^x)^2}$
Exponential Differentiation: $\displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x}{(e^x)^2}$
Simplify: $\displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x}{e^{2x}}$
Rewrite: $\displaystyle f'(x) = \bigg( \frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x \bigg) e^{-2x}$
Factor: $\displaystyle f'(x) = \bigg( \frac{1}{2\sqrt{x}} - \sqrt{x} \bigg)e^\big{-x}$