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3 years ago

How many significant figures does 0.0560 have?

Mathematics

1 answer:

Goryan [66]3 years ago

8 0

3 significant figures

The 0.0 is not significant, but the 560 is

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For which x is f(x)?=-3

musickatia [10]

Answer:

$-7$

Step-by-step explanation:

$f(-3)=-7$

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Match the term with the definition

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Answer:

Plane: C) A flat surface that extends infinitively and has no depth; it has length and width

Perpendicular Lines: B) Two lines that intersect at 90° angles

Parallel Lines: E) Two lines that lie within the same plane and never intersect

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this is 100% correct

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3 years ago

❊ Simplify :

DiKsa [7]

Answer:

See Below.

Step-by-step explanation:

Problem 1)

We want to simplify:

$\displaystyle \frac{a+2}{a^2+a-2}+\frac{3}{a^2-1}$

First, let's factor the denominators of each term. For the second term, we can use the difference of two squares. Hence:

$\displaystyle =\frac{a+2}{(a+2)(a-1)}+\frac{3}{(a+1)(a-1)}$

Now, create a common denominator. To do this, we can multiply the first term by (a + 1) and the second term by (a + 2). Hence:

$\displaystyle =\frac{(a+2)(a+1)}{(a+2)(a-1)(a+1)}+\frac{3(a+2)}{(a+2)(a-1)(a+1)}$

Add the fractions:

$\displaystyle =\frac{(a+2)(a+1)+3(a+2)}{(a+2)(a-1)(a+1)}$

Factor:

$\displaystyle =\frac{(a+2)((a+1)+3)}{(a+2)(a-1)(a+1)}$

Simplify:

$\displaystyle =\frac{a+4}{(a-1)(a+1)}$

We can expand. Therefore:

$\displaystyle =\frac{a+4}{a^2-1}$

Problem 2)

We want to simplify:

$\displaystyle \frac{1}{(a-b)(b-c)}+\frac{1}{(c-b)(a-c)}$

Again, let's create a common denominator. First, let's factor out a negative from the second term:

$\displaystyle \begin{aligned} \displaystyle &= \frac{1}{(a-b)(b-c)}+\frac{1}{(-(b-c))(a-c)}\\\\&=\displaystyle \frac{1}{(a-b)(b-c)}-\frac{1}{(b-c)(a-c)}\\\end{aligned}$

Now to create a common denominator, we can multiply the first term by (a - c) and the second term by (a - b). Hence:

$\displaystyle =\frac{(a-c)}{(a-b)(b-c)(a-c)}-\frac{(a-b)}{(a-b)(b-c)(a-c)}$

Subtract the fractions:

$\displaystyle =\frac{(a-c)-(a-b)}{(a-b)(b-c)(a-c)}$

Distribute and simplify:

$\displaystyle =\frac{a-c-a+b}{(a-b)(b-c)(a-c)}=\frac{b-c}{(a-b)(b-c)(a-c)}$

Cancel. Hence:

$\displaystyle =\frac{1}{(a-b)(a-c)}$

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3 years ago

A map of your town has a scale of 1 inch to 0.25 mile. There are two roads that are 5 inches apart on the map. Use this informat

egoroff_w [7]

Answer: The 2 roads are 1.25 miles apart.

Step-by-step explanation:

If 1 inch equals .25 miles, then you need to multiply .25 by 5.

Use proportions. Make sure the miles are on the same "side" of the fraction. Side meaning the top or the bottom

$\frac{1}{.25} =\frac{5}{x}$

1 times X equals 1x

.25 times 5 equals 1.25

1.25 divided by 1 equals 1.25.

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