Which is the domain of the function f(x) = -
1 answer:
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Remark
The idea here is to take any two successive terms and divide one by the other. which is the divisor and which the dividend will be discussed below.
Step One
Set up the ratio for the common ratio between terms that come one after another.
Mathematically this is written as
r =
So just to see how this looks
t_(n + 1) = 3
t_n = 9
r =
r = 1/3
Does this work for other examples? Let's try a more complicated looking one.
t_(n) = 1/9
t_(n+1) = 1/27
r = t_(n + 1) / t_n
r =
r =
r = 1/3
The idea here is to take any two successive terms and divide one by the other. which is the divisor and which the dividend will be discussed below.
Step One
Set up the ratio for the common ratio between terms that come one after another.
Mathematically this is written as
r =
So just to see how this looks
t_(n + 1) = 3
t_n = 9
r =
r = 1/3
Does this work for other examples? Let's try a more complicated looking one.
t_(n) = 1/9
t_(n+1) = 1/27
r = t_(n + 1) / t_n
r =
r =
r = 1/3
So the line that is the limit is where the equation crosses the y axis or where x=0
so
y=(1/2(0)-2)^2+5
y=(-2)^2+5
y=4+5
y=9
at y=9
the upper bound is y=9
alrighty
we will do
let's call the curve that is 6th degree f(x)
and the y=9, g(x)
f(x)=(1/2x-2)^6+5
g(x)=9
find where they intersect
9=(1/2x-2)^6+5
4=(1/2x-2)^6
fancy math
x=8
so the area under the curve will be
because g(x) is above f(x)
so
using our calculator because I can't figure out what
is
or about 21.33333333
so
y=(1/2(0)-2)^2+5
y=(-2)^2+5
y=4+5
y=9
at y=9
the upper bound is y=9
alrighty
we will do
let's call the curve that is 6th degree f(x)
and the y=9, g(x)
f(x)=(1/2x-2)^6+5
g(x)=9
find where they intersect
9=(1/2x-2)^6+5
4=(1/2x-2)^6
fancy math
x=8
so the area under the curve will be
so
using our calculator because I can't figure out what