The question ask to find the angle between the given vector to the nearest tenth of a degree and base on the value or the coordinates of each vector, the possible value of the angle base on the said vectors is 1.8 degree. I hope you are satisfied with my answer and feel free to ask for more
The line to find: y = mx + b
the line perpendicular to y= 2/5x+6/6 so it has the slope m × 2/5 = -1
thus the slope m = -5/2
the line passes through the point (-2,6) so:
6 = (-5/2)×(-2) + b so b = 1
the equation of the line is y = -5/2x +1
Step-by-step explanation:
y - 3 = -1(x- -2)
y-3 = -x -2
Y = -x +1
Answer:
whos mad im not mad you mad PERIOD
Step-by-step explanation:
This area is equal to the sum of a circle with a radius of 5/2 in and a rectangle 5 by 15 in so:
A=πr^2+xy
A=π(2.5)^2+5*15
A=6.25π+75 in^2
A≈94.63 in^2 (to nearest hundredth) so
A≈95 in^2 (to nearest whole square inch)
