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sladkih [1.3K]
3 years ago
7

You and a friend are running on treadmills. you run 0.5 mile every 3 minutes and your friend runs 2 miles every 14 minutes. you

both start and stop running at the same time and run a whole number of miles. what is the least possible number of miles you and your friend can run?
Mathematics
2 answers:
Natali5045456 [20]3 years ago
4 0
I run 1 mile every 6 minutes.
My friend runs 1 mile every 7 minutes.
Lowest Common Multiple:  LCM ( 6, 7 ) = 42 minutes.
Me : 42 : 6 = 7 miles
My friend : 42 : 7 = 6 miles. 

rosijanka [135]3 years ago
4 0
Start by finding how long it takes each to run 1 mile.

You: 0.5 mile every 3 minutes => 1 mile every 6 minutes

Your friend 2 miles every 14 minutes => 1 mile every 7 minutes

Now you have to calculate the minimum common multiple of 6 and 7.

For that you need to factor both numbers and take common and non common factors raised to their highest exponent:

6 = 3*2
7 = 7

Then the minimum common multiple is 2*3*7=42.

Now divide the time 42 by the humber of minutes each of you take to run 1 mile

you: 42 minutes / 6 minutes per mile = 7 miles
your friend 42 minutes / 7 minutes per mile = 6 miles.

You can run 7 miles and your friend 6 miles in the same time.

Answer: 7 and 6

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In the last year, U.S. car sales of all makes and models have dropped by 16%. Let's say that a car dealer sells 325 cars. If thi
IRINA_888 [86]

Answer:

c. 273 cars

Step-by-step explanation:

First you need to find what 16% of 325 is

325x.16=52

because the number sold dropped by 16% you will subtract 52 from 325

325-52=273

you can also calculate the answer by subtracting 100% by 16%

100%-16%=84%

now you can calculate 84% of 325

325x.84=273

6 0
3 years ago
A student repeatedly measures the mass of an object using a mechanical balance and gets the following values: 560 g, 562 g, 556
MrRissso [65]

Answer: 2.76 g

Step-by-step explanation:

The formula to find the standard deviation:-

\sigma=\sqrt{\dfrac{\sum(x_i-\overline{x})^2}{n}}

The given data values : 560 g, 562 g, 556 g, 558 g, 560 g, 556 g, 559 g, 561 g, 565 g, 563 g.

Then,  \overline{x}=\dfrac{\sum_{i=1}^{10} x_i}{n}\\\\\Rightarrow\ \overline{x}=\dfrac{560+562+556+558+560+556+559+561+565+563}{10}\\\\\Rightarrow\ \overline{x}=\dfrac{5600}{10}=560

Now, \sum_{i=1}^{10}(x_i-\overline{x})^2=0^2+2^2+(-4)^2+(-2)^2+0^2+(-4)^2+(-1)^2+1^2+5^2+3^2\\\\\Rightarrow\ \sum_{i=1}^{10}(x_i-\overline{x})^2=76

Then, \sigma=\sqrt{\dfrac{76}{10}}=\sqrt{7.6}=2.76

Hence, the  standard deviation of his measurements = 2.76 g

6 0
4 years ago
Please helppp meeeeeeee
natka813 [3]

Answer:

i dont know if this is right but i think that would be the second one

Step-by-step explanation:

i dont know if this is right but i think that would be the second one

3 0
3 years ago
Select all the expressions that have a value of 180 when b = 4. o 876 – 179 + 957 - 87 O 336 12 62 + 120 0 516 - 24 ( 115 + 187
BabaBlast [244]

Answer: miata

Step-by-step explanation:

6 0
3 years ago
19)
Elena-2011 [213]

Answer:

The correct answer is: Option D) 5

Step-by-step explanation:

Given equation is:

3(x + 2) + x = 2x + 16

In order to find that which values of x makes the equation true, we have to put each value of x in the equation. When both sides of equations will be equal, that value of x will be true for the equation.

Putting x = 2

3(2 + 2) + 2 = 2(2) + 16\\3(4)+2 = 4+16\\12+2 = 20\\14 \neq 20

Putting x = 3

3(3 + 2) + 3 = 2(3) + 16\\3(5)+3 = 6+16\\17+3 = 22\\20 \neq 22

Putting x=4

3(4+2)+4 = 2(4)+16\\3(6)+4 = 8+16\\18+4 = 24\\22 \neq 24

Putting x = 5

3(5+2)+5 = 2(5)+16\\3(7)+5 = 10+16\\21+5 = 26\\26 = 26

The equation is true for x = 5

Hence,

The correct answer is: Option D) 5

6 0
3 years ago
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