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Gemiola [76]
3 years ago
6

Raj weighs a book and rounds the weights to the nearest tenth. Does this weight round to 1.5 pounds?

Mathematics
1 answer:
Archy [21]3 years ago
7 0

Answer:

Its false

Step-by-step explanation:

4.42 the .42 the 2 is under 5 so it would round up.

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Find the measure of X
melomori [17]

Answer:

7

Step-by-step explanation:

135 = 15*(x+2)

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Solve the equations using the substitution method:<br> 4x -2y =22<br> 2x + 4y = 6
Ugo [173]
We have that
<span>4x -2y =22------> clear variable y
2y=4x-22--------> y=4x/2-22/2---------> y=2x-11-----> equation 1
2x + 4y = 6------> equation 2

substitute equation 1 in equation 2
2x+4*[2x-11]=6-----> 2x+8x-44=6----> 10x=50------> x=5
then 
y=2x-11----> y=2*5-11----> y=-1


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4 0
2 years ago
Does (3,5) and (-3,-5) lie in the same quadrant
Arlecino [84]

Answer:

no they don't one lies in  quadrant 1 while the other is in quadrant 3

Step-by-step explanation:

4 0
3 years ago
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Write the following equation in slope -intercept form : y - 3 = 4(x + 2)​
andreyandreev [35.5K]

Answer:

y=4x+11

Step-by-step explanation:

multiply 4 into the parentheses to get y-3=4x+8 then invert -3 so add three to both sides to get rid of it so instead of +8 its +11 so now its y=4x+11 and slope intercept is y=mx+b, so 4 is m, slope, and 11 is b, the y intercept i hope that helps

7 0
3 years ago
Estimate the following quantities without using a calculator. Then find a more precise result, using a calculator if necessary.
zubka84 [21]

Explanation:

a. It is so easy to double a number that no approximation is necessary.

  31,000 × 200 = 3.1×10⁴ × 2×10² = 6.2×10⁶ exactly

__

b. 6.2×10³ × 5.2×10⁶ ≈ 6×5×10⁹ = 3×10¹⁰ approximately

The approximation can be refined a bit by taking the ".2" into account:

  6.2×10³ × 5.2×10⁶ ≈ (6×5 + .2×(6+5))×10⁹

  = 32.2×10⁹ = 3.22×10¹⁰ approximately

Actual product: 3.224×10¹⁰.

For most purposes, the approximation is an adequate approximation, as it it within 10% of the actual value.

__

c. 9×10⁶ -2.3×10⁴ ≈ 9×10⁶ approximately

A better approximation is to actually subtract an approximation of the smaller number:

  9×10⁶ -2.3×10⁴ ≈ (9 - 0.02)×10⁶ ≈ 8.98×10⁶ approximately

The actual value uses all of the digits of the smaller number:

  9×10⁶ -2.3×10⁴ ≈ (9 - 0.023)×10⁶ = 8.977×10⁶ exactly

As in part B, either approximation is adequate for most purposes, as the difference from the actual value is less than .3%.

_____

The accuracy required of an approximation, hence the work you expend improving accuracy, should depend on the need in the final application of the number. Often, approximations are used for budget or resource planning purposes where some "slop" is allowed or even expected.

They can also be used in engineering applications, where the error needs to be on the side of more safety (rather than less).

7 0
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