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Ludmilka [50]
3 years ago
10

What is cos (x)? A) 48/58 B) 58/48 C) 26/58 D) 58/26

Mathematics
1 answer:
arsen [322]3 years ago
7 0
Remark
In order to solve for the Cos(x), you need to find the missing side. You can do that by finding the Sin(x) first and then the Cos of x or you can just use the Pythagorean theorem. I'm going to do the latter.

Formula
a^2 + b^2 = c^2

Givens
a = ???
b = 32
c = 58

Sub and solve
a^2 = ???
b^2 = 1024
c^2 = 3364

a^2 + 32^2 = 58^2
1024 + a^2 = 3364  Subtract 1024 from both sides.
a^2 = 3364 - 1024
a^2 = 2340              Take the square root of both sides.
sqrt(a^2) = sqrt(2340) Break a into its prime factors.
a = sqrt(2 * 2 * 5 * 3 * 3 * 13)

Rule
For every pair of equal factors, one can be brought outside the root sign and the other is discarded.
a = 2 * 3 * sqrt(5*13)
a = 6 sqrt(65)

The cos of an angle = opposite / hypotenuse.
Cos(x) = 6*sqrt(65) / 58 <<<<< This should be the answer
If you are offered choices, you should list them

Another choice would be 6*8.0623 / 58 = 0.8340  <<<<< Answer



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x-------> the number of persons in the family

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The domain of the function  would only include positive integers, because the number of persons can not be negative or a fraction

The range of the function would only include positive numbers, because the cost can not be negative

therefore

<u>the answer is the option B</u>

The domain would only include positive integers.

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Make w the subject of the formula y - aw = 2w - 1
Salsk061 [2.6K]

Answer:

w=\frac{y+1}{a-2} (a\neq 2)

Step-by-step explanation:

y - aw=2w-1\\y-aw-2w=-1\\-aw-2w=-1-y\\-w(a-2)=-(y+1)\\w(a-2)=y+1\\w=\frac{y+1}{a-2} (a\neq 2)

Hope this helps!

6 0
2 years ago
Find the perimeter of the triangle defined by the coordinates (9, 0), (-5, 0), and (-10, 6). (Round to nearest tenth)
eduard
The perimeter is 41.7.

We first find the distance between each vertex using the distance formula:
d=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}&#10;\\&#10;\\=\sqrt{(0-0)^2+(-5-9)^2}=\sqrt{0^2+(-14)^2}=\sqrt{196}=14&#10;\\&#10;\\d=\sqrt{(6-0)^2+(-10--5)^2}=\sqrt{6^2+(-5)^2}=\sqrt{36+25}=\sqrt{61}&#10;\\=7.81&#10;\\&#10;\\d=\sqrt{(6-0)^2+(-10-9)^2}=\sqrt{6^2+(-19)^2}=\sqrt{36+361}=\sqrt{397}&#10;\\=19.92

We now find the perimeter by adding all of the side lengths:
14+7.81+19.92 = 41.73 ≈ 41.7
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3 years ago
Help with geometry please !
aliina [53]
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8x-7x = 18
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6 0
2 years ago
Find the sum of the first 8 terms of the following series, to the nearest integer.
motikmotik

Answer:

The sum of the first 8 terms will be:

  • \frac{1288991}{7776}

Step-by-step explanation:

Given the sequence

36, 30, 25, ...

A geometric sequence has a constant ratio and is defined by

a_n=a_0\cdot r^{n-1}

computing the common ratio

\frac{30}{36}=\frac{5}{6},\:\quad \frac{25}{30}=\frac{5}{6}

r=\frac{5}{6}

As the first element is

a_1=36

so the nth term will be:

a_n=a_0\cdot r^{n-1}

a_n=36\left(\frac{5}{6}\right)^{n-1}

Geometric sequence sum formula

a_1\frac{1-r^n}{1-r}

Plugin the values to determine the sum of the first 8 terms

n=8,\:\spacea_1=36,\:\spacer=\frac{5}{6}

=36\cdot \frac{1-\left(\frac{5}{6}\right)^8}{1-\frac{5}{6}}

=\frac{\left(1-\left(\frac{5}{6}\right)^8\right)\cdot \:36}{1-\frac{5}{6}}    

=\frac{36\left(-\left(\frac{5}{6}\right)^8+1\right)}{\frac{1}{6}}

=\frac{36\left(-\frac{390625}{1679616}+1\right)}{\frac{1}{6}}

=\frac{\left(1-\frac{390625}{1679616}\right)\cdot \:36\cdot \:6}{1}

=\frac{216\left(-\frac{390625}{1679616}+1\right)}{1}

=\frac{216\cdot \frac{1288991}{1679616}}{1}

=216\cdot \frac{1288991}{1679616}

=\frac{1288991\cdot \:216}{1679616}

=\frac{278422056}{1679616}

=\frac{1288991}{7776}

 Therefore, the sum of the first 8 terms will be:

  • \frac{1288991}{7776}
7 0
2 years ago
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