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alexandr1967 [171]

3 years ago

15

Whenever one object exerts a force on another object, the second object exerts a force of the same magnitude on the first object

, but in the opposite direction

1 answer:

Naddik [55]3 years ago

6 0

Answer:

A

Explanation:

Newton third law of motion state that action and reaction are equal and opposite

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Coach ulcer paces the sidelines. Sarting at the 30 yd. line (A), he moves to the 10 yd. line (B), back to the 50 yd. line (C) an

Katarina [22]

Answer:

See the answer below

Explanation:

<em>Average speed = total distance traveled/total time taken</em>

In order to determine the total distance traveled by the coach, consider the attached image.

Distance covered:

30 yd. line to 10 yd. line (A to B)= 20 yds

10 yd. line to 50 yd. line (B to C) = 40 yds

50 yd. line to 20 yd. line (C to D) = 30 yds

Total distance covered = 20 + 40 + 30 = 90 yds

Time taken = 200 seconds

Average Speed = 90/200 = <em>0.45 yd/s</em>

<em>Velocity = speed with direction</em>

Hence,

His Velocity = <em>0.45 yd/s to the left of his starting point.</em>

7 0

3 years ago

1. Si tengo medio kilo de fruta y te doy un cuarto y tú me das tres cuartos de kilo, ¿cuánto tengo? 2. Si en una carrera te qued

Kipish [7]

Answer:

1. Tienes 1 kg de fruta.

2. Queda por recorrer 1/4 km.

3. Ambos pesan lo mismo.

Explanation:

1. Tienes 1/2 kg y cuando te doy 1/4 te queda:

$m = \frac{1}{2} - \frac{1}{4} = \frac{1}{4}$

Ahora cuando te doy 3/4 kg te queda en total:

$m_{T} = \frac{1}{4} + \frac{3}{4} = 1 kg$

Por lo tanto, tienes 1 kg de fruta al final.

2. Si falta por recorrer la mitad de la mitad, tenemos:

$d = \frac{1/2}{2} = \frac{1}{4}$

Entonces, queda por recorrer 1/4 km.

3. El peso (P) del hierro es:

$P = m*g$

$P = (1 + 1/2)kg*9.81 m/s^{2} = 14.72 N$

Y el peso de la paja es:

$P = 3/2 kg*9.81 m/s^{2} = 14.72 N$

Por lo tanto, ambos pesan lo mismo.

Espero que te sea de utilidad!

6 0

3 years ago

HELP! A helicopter winches up an injured person from a boat. The person plus the equipment that must be pulled up with the perso

Marat540 [252]

When a person is pulled upwards why the motor of the helicopter

Then the potential energy increased of the person is given as

$U = mgh$

here m = 109 kg

h = 83 m

so here potential energy of the person given as

$U = 109*9.8*83$

$U = 88660.6 J$

now power is defined as rate of energy

so it took 55 s to pull the mass so power is given as

$P = \frac{U}{t} = \frac{88660.6}{55} = 1612 W$

now we know that efficiency of motor is given as 69%

so we have

$efficiency = \frac{output}{input}$

$0.69 = \frac{1612}{P}$

so we have power as

$P = \frac{1612}{0.69} = 2336.2 W$

4 0

3 years ago

A meter stick is place in a very high-speed spaceship. What length would the astronauts say the meter stick was? What would the

Marysya12 [62]

Answer:

a) The astronauts would see the real length of the meter stick, i.e. L₀

b) The length of the meter stick as measured by the stationary observer will be $L = L_{0} }{\sqrt{(1-(\frac{v}{c} )^{2} } }$

Explanation:

a) Let the proper length of the meter stick be L₀

The meter stick and the astronauts on the on the space ship are on the same moving frame, therefore, they will see the exact length of the meter stick, that is, L₀

b) A stationary observer watching the space ship and meter stick travel past them will see a contracted length of the meter stick

The original length = L₀

Let the speed of the space ship = v

The contracted length, L, is related to the original length in the frame of rest by

L = L₀/γ......................(1)

Where γ = $\frac{1}{\sqrt{(1-(\frac{v}{c} )^{2} } }$ ....................(2)

Substituting equation (2) into (1)

$L = L_{0} }{\sqrt{(1-(\frac{v}{c} )^{2} } }$

4 0

3 years ago

PLS HELP, WILL GIVE BRAINLIEST

PtichkaEL [24]

Answer:

A

Explanation:

Hope this helps and have a wonderful day!!!

5 0

3 years ago

Read 2 more answers