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3 years ago

A sound wave has a wavelength of 0.450 meters . If is a speed in cold air 330 meters / seconds what is waves frequency

Physics

1 answer:

koban [17]3 years ago

6 0

The wave frequency would be 733 because you divide the two numbers together to get the answer.

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Determine the velocity (in m/s) of the object during the first three seconds. Include a numerical answer accurate to the first d

OlgaM077 [116]

If it’s moved 3m in 3s then it should be 3m/s

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3 years ago

Which system works with the respiratory system for the exchange of gases to take place?

4vir4ik [10]

Yep it is. Defiantly the circulatory system

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3 years ago

A point charge with a charge q1 = 2.30 μC is held stationary at the origin. A second point charge with a charge q2 = -5.00 μC mo

Alla [95]

Answer:

W = 2.74 J

Explanation:

The work done by the charge on the origin to the moving charge is equal to the difference in the potential energy of the charges.

This is the electrostatic equivalent of the work-energy theorem.

$W = \Delta U = U_2 - U_1$

where the potential energy is defined as follows

$U = \frac{1}{4\pi\epsilon_0}\frac{q_1q_2}{r^2}$

Let's first calculate the distance 'r' for both positions.

$r_1 = \sqrt{(x_1 - x_0)^2 + (y_1 - y_0)^2} = \sqrt{(0.170 - 0)^2 + (0 - 0)^2} = 0.170~m\\r_2 = \sqrt{(x_2 - x_0)^2 + (y_2 - y_0)^2} = \sqrt{(0.250 - 0)^2 + (0.250 - 0)^2} = 0.353~m$

Now, we can calculate the potential energies for both positions.

$U_1 = \frac{kq_1q_2}{r_1^2} = \frac{(8.99\times 10^9)(2.3\times 10^{-6})(-5\times 10^{-6})}{(0.170)^2} = -3.57~J\\U_2 = \frac{kq_1q_2}{r_2^2} = \frac{(8.99\times 10^9)(2.3\times 10^{-6})(-5\times 10^{-6})}{(0.3530)^2} = -0.829~J$

Finally, the total work done on the moving particle can be calculated.

$W = U_2 - U_1 = (-0.829) - (-3.57) = 2.74~J$

4 0

3 years ago

Read 2 more answers

A cylinder has a magnetic flux of 13 Wb directed inward through its bottom end, and a magnetic flux of 22 Wb directed out of the

satela [25.4K]

To give a solution to this exercise, it is necessary to apply Gauss's magnetic law in which he proposes the magnetic flux through closed surface is zero.

Our data given are as follows:

Inward flux = 13Wb

Outward flux = 22Wb

Since the field of the second flow is directed OUT of the curved side we need to subtract the values, therefore,

Flux = 22-13

$Flux = 9Wb\Rightarrow INWARD.$

4 0

3 years ago

PLEASE HELP , THOSE ARE ALL THE ANSWERS!

insens350 [35]

Answer:

I don't understand

Explanation:

7 0

3 years ago

Read 2 more answers