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victus00 [196]
3 years ago
8

Coach ulcer paces the sidelines. Sarting at the 30 yd. line (A), he moves to the 10 yd. line (B), back to the 50 yd. line (C) an

d finally to the 20yd. Line (D) in 200 seconds. Determine his average speed and velocity.
Physics
1 answer:
Katarina [22]3 years ago
7 0

Answer:

See the answer below

Explanation:

<em>Average speed = total distance traveled/total time taken</em>

In order to determine the total distance traveled by the coach, consider the attached image.

Distance covered:

30 yd. line to 10 yd. line (A to B)= 20 yds

10 yd. line to 50 yd. line (B to C) = 40 yds

50 yd. line to 20 yd. line (C to D) = 30 yds

Total distance covered = 20 + 40 + 30 = 90 yds

Time taken = 200 seconds

Average Speed = 90/200 = <em>0.45 yd/s</em>

<em>Velocity = speed with direction</em>

Hence,

His Velocity = <em>0.45 yd/s to the left of his starting point.</em>

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Given;

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