Answer:
See the answer below
Explanation:
<em>Average speed = total distance traveled/total time taken</em>
In order to determine the total distance traveled by the coach, consider the attached image.
Distance covered:
30 yd. line to 10 yd. line (A to B)= 20 yds
10 yd. line to 50 yd. line (B to C) = 40 yds
50 yd. line to 20 yd. line (C to D) = 30 yds
Total distance covered = 20 + 40 + 30 = 90 yds
Time taken = 200 seconds
Average Speed = 90/200 = <em>0.45 yd/s</em>
<em>Velocity = speed with direction</em>
Hence,
His Velocity = <em>0.45 yd/s to the left of his starting point.</em>
To solve this problem it is necessary to apply the concepts related to Sound Intensity. The unit most used in the logarithmic scale is the decibel and mathematically this is expressed as
Where,
= Sound intensity level in decibels
I = Acoustic intensity on the linear scale
Hearing threshold
According to the values, the total intensity is 32 times the linear intensity and the value in decibels is 83dB
So:
Therefore the sound intensity due to one person is 67.948dB
Answer:
Explanation:
As we know that the angle made with the vertical is given so we have
so we have
now differentiate both sides with time
now we know that
now we have