Hey will you pleas help meh ☆
1 answer:
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Answer:
The value of y is 5 , and The value of x is - 5
Step-by-step explanation:
Given as :
The line passes through point ( - 2, 5)
The slope of line is m =
Equation of line is written as
y - = m × (x -
)
Since line passes through line ( - 2 , 5 ) and have slope
So, y - 5 = × (x + 2)
Or, 3 × ( y - 5 ) = 2 × ( x + 2 )
Or, 3 y - 15 = 2 x + 4
Or, 3 y - 2 x - 19 = 0 is the equation of line
Now points ( x , 3 ) lies on the line 3 y - 2 x - 19 = 0
So, 3 × 3 - 2 x - 19 = 0
or, 9 - 2 x - 19 = 0
or, 2 x = - 10
∴ x = -
I.e x = - 5
Again points ( - 2 , y ) lies on the line 3 y - 2 x - 19 = 0
So, 3 × y + 2 × 2 - 19 = 0
Or, 3 × y + 4 -19 = 0
or, 3 y = 15
∴ y =
I.e y = 5
Hence The value of y is 5 , and The value of x is - 5 . Answer
*see attachment for the missing figure
Answer:
Angle ADE = 45°
Angle DAE = 30°
Angle DEA = 105°
Step-by-step explanation:
Since lines AD and BC are parallel, therefore:
Given that angle Angle CBE = 45°,
Angle ADE = Angle CBE (alternate interior angles are congruent)
Angle ADE = 45° (Substitution)
Angle DAE = Angle ACB (Alternate Interior Angles are congruent)
Angle ACB = 180 - 150 (angles on a straight line theorem)
Angle ACB = 30°
Since angle DAE = angle ACB, therefore:
Angle DAE = 30°
Angle DEA = 180 - (angle ADE + angle DAE) (Sum of angles in a triangle)
Angle DEA = 180 - (45 + 30) (Substitution)
Angle DEA = 180 - 75
Angle DEA = 105°
