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Korvikt [17]
4 years ago
7

Which of the following is the sine of angle A in the right triangle shown?

Mathematics
2 answers:
maks197457 [2]3 years ago
6 0
Ans is B cuz' BC/AC = 12/13
egoroff_w [7]3 years ago
3 0

sinA=BC/AC=12/13

ans is B

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Quizziz helpiurhgipuwqb;qor
Amiraneli [1.4K]

Answer:

Ummm -6 and -4

Step-by-step explanation:

Duh

3 0
3 years ago
Helpppppp me right now!
Rudik [331]

Answer:

B and D

7/12 cups

Step-by-step explanation:

2 1/3 + 2 1/4 = cups of flour needed

4 = cups of flour had

2 1/3 + 2 1/4

To have the same denominator, we take the lcm

2 + 2 + (4/12 + 3/12) =

2 4/12 + 2 3/12 - 4

Or

2 + 2 + (3 + 4) / 12 - 4

2 + 2 + (3 + 4) / 12 - 4 = 4 7/12 - 4

4 7/12 - 4 = 7/12 cups of flour needed

8 0
3 years ago
Which of these statements best describes the relation shown in Item 1?
Misha Larkins [42]

Answer:

It is a many-to-one relation

Step-by-step explanation:

Given

See attachment for relation

Required

What type of function is it?

The relation can be represented as:

\left[\begin{array}{c}x\\ \\-5\\-2\\1\\5\end{array}\right]         \left[\begin{array}{c}y\\ \\10\\11\\4\\10\end{array}\right]

Where

x = domain and y = range

Notice that the range has an occurrence of 10 (twice)

i.e.

(x_1,y_1) = (-5,10) and (x_2,y_2) = (5,10)

In function and relations, when two different values in the domain point to the same value in the range implies that, <em>the relation is many to one.</em>

8 0
3 years ago
Dirk plants 12 seedlings in 8 min. At this rate, how many seedlings could he plant in 70 min?
Zigmanuir [339]
The answer to this question is B. 105
8 0
3 years ago
A.
Reptile [31]

Answer:

The real zeros of f(x) are x = 0.3 and x = -3.3.

Step-by-step explanation:

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = a(x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}

x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}

\bigtriangleup = b^{2} - 4ac

In this problem, we have that:

f(x) = x^{2} + 3x - 1

So

a = 1, b = 3, c = -1

\bigtriangleup = 3^{2} - 4*1*(-1) = 13

x_{1} = \frac{-3 + \sqrt{13}}{2*1} = 0.3

x_{2} = \frac{-3 - \sqrt{13}}{2*1} = -3.3

The real zeros of f(x) are x = 0.3 and x = -3.3.

7 0
3 years ago
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