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vlada-n [284]
3 years ago
5

The sum of the differences must be zero for any distribution consisting of n observations.

Mathematics
1 answer:
Semenov [28]3 years ago
7 0

Answer:

false

Step-by-step explanation:

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20 increased by twice Greg's savings<br> Use the variable g to represent Greg's savings.
Sophie [7]
40g
20 + 20=40
Sorry if I’m wrong
4 0
2 years ago
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What is the slope of the line passing through (-3, 5) and (5, -3)?
Slav-nsk [51]
Dy/dx, ie., the difference in y divided by the difference in x. If you have two points A and B, sort them in ascending order of x.

dx = 5 - -3 = 8 (x coordinates of B minus x coordinate of A)
dy = -3 - 5 = -8 (y coordinate of B minus y coordinate of A)

dy/dx = -1

So the slope is -1. The equation of the line is y=2-x.
5 0
3 years ago
Which expression is equivalent to (3a)–2?
Travka [436]

Answer:

Its (A), 1/9a^2

if you work out all of the other options it does not equal to the expression (3a)^-2

Step-by-step explanation:

7 0
2 years ago
Shelia's measured glucose level one hour after a sugary drink varies according to the normal distribution with μ = 117 mg/dl and
TiliK225 [7]

Answer:

The level L such that there is probability only 0.01 that the mean glucose level of 6 test results falls above L is L = 127.1 mg/dl.

Step-by-step explanation:

To solve this problem, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit Theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 117, \sigma = 10.6, n = 6, s = \frac{10.6}{\sqrt{6}} = 4.33

What is the level L such that there is probability only 0.01 that the mean glucose level of 6 test results falls above L ?

This is the value of X when Z has a pvalue of 1-0.01 = 0.99. So X when Z = 2.33.

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

2.33 = \frac{X - 117}{4.33}

X - 117 = 2.33*4.33

X = 127.1

The level L such that there is probability only 0.01 that the mean glucose level of 6 test results falls above L is L = 127.1 mg/dl.

6 0
3 years ago
What is tan 30°?<br> 60'<br> 2<br> 1<br> 90<br> 30"
Lemur [1.5K]

Answer:

Option F. 1/√3

Step-by-step explanation:

From the question given above, the following data were obtained:

Angle θ = 30°

Opposite = 1

Adjacent = √3

The value of Tan 30° can be obtained as illustrated below:

Tan θ = Opposite / Adjacent

Tan 30 = 1/√3

Thus, the value of Tan 30° is 1/√3

8 0
2 years ago
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