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2 years ago

Can I get some help

Mathematics

1 answer:

Mariulka [41]2 years ago

5 0

Given:

The expression is

$2x^4+2x^3-x^2-x$

The steps are given.

To find:

The mistake in her steps.

Solution:

We have,

$2x^4+2x^3-x^2-x$

The correct steps are shown below.

Step 1: Taking out x as common factor.

$=x(2x^3+2x^2-x-1)$

Step 2: Now, taking out 2x² as common factor from first two terms (first group of terms) and -1 form last two terms (second group of terms) in the parentheses.

$=x(2x^2(x+1)-1(x+1))$

Step 3: Taking out (x+1) as common factor.

$=x(2x^2-1)(x+1)$

She incorrectly factored -1 from the second group of terms.

Therefore, the correct option is B.

You might be interested in

Please help thank you.

Marizza181 [45]

Area of the full circle would be PI x r^2 = PI x 6^2 = 36 *3.14 = 113.04

the angle is 165

so area = 165/360 x 113.04

area = 51.8 in^2

answer is B

7 0

3 years ago

How do I factor trinomials of a form ax^2+bx+c when a=1 <br><br> In one paragraph

vitfil [10]

Answer:

Trinomials in the form $x^2+bx+c$ can often be factored as the product of two binomials.

Step-by-step explanation:

As we know that a polynomial with three terms is said to be a trinomial.

Considering the trinomial of a form

$ax^2+bx+c$

a = 1

$x^2+bx+c$

Trinomials in the form $x^2+bx+c$ can often be factored as the product of two binomials.

For example,

$x^2+7x+10$

$=\left(x^2+2x\right)+\left(5x+10\right)$

$=x\left(x+2\right)+5\left(x+2\right)$

$\mathrm{Factor\:out\:common\:term\:}x+2$

$=\left(x+2\right)\left(x+5\right)$

Therefore, Trinomials in the form $x^2+bx+c$ can often be factored as the product of two binomials.

6 0

2 years ago

How long does it take a car to travel 200 mi at a constant speed of 25 mi/h?

beks73 [17]

First you have to do $200/25=8$ .
Since the car is moving at a constant rate, the answer would be 8h.

7 0

3 years ago

Read 2 more answers

six times jason collection of books and one third of nathan collection add up to 134 books. one third of jason collection and na

raketka [301]

Answer:

j = 21 and n = 14

Step-by-step explanation:

we have the equations:

6j + n/3 = 134

j/3 + n = 31

54j + 3n = 1206

j + 3n = 93

53j = 1113

j = 21

(21)/3 + n = 31

7 + n = 31

n = 14

6 0

3 years ago

You are jumping off the 12 foot diving board at the municipal pool. You bounce up at 6 feet per second and drop to the water you

NARA [144]

Answer:

When do you hit the water?

1.075 seconds after you jump.

What is your maximum height?

the maximum height is 12.5626 ft

Step-by-step explanation:

The equation:

h(t) = -16*t^2 + 6*t + 12

Is the height as a function of time.

We know that the initial height is the height when t = 0s

h(0s) = 12

and we know that the diving board is 12 foot tall.

Then the zero in h(t)

h(t) = 0

Represents the surface of the water.

When do you hit the water?

Here we just need to find the value of t such that:

h(t) = 0 = -16*t^2 + 6*t + 12

Using the Bhaskara's formula, we get:

$t = \frac{-6 \pm \sqrt{6^2 - 4*(-16)*12} }{2*(-16)} = \frac{-6 \pm 28.4}{-32}$

Then we have two solutions, and we only care for the positive solution (because the negative time happens before the jump, so that solution can be discarded)

The positive solution is:

t = (-6 - 28.4)/-32 = 1.075

So you hit the water 1.075 seconds after you jump.

What is your maximum height?

The height equation is a quadratic equation with a negative leading coefficient, then the maximum of this parabola is at the vertex.

We know that the vertex of a general quadratic:

a*x^2 + b*x + c

is at

x = -b/2a

Then in the case of our equation:

h(t) = -16*t^2 + 6*t + 12

The vertex is at:

t = -6/(2*-16) = 6/32 = 0.1875

Evaluating the height equation in that time will give us the maximum height, which is:

h(0.1875) = -16*(0.1875 )^2 + 6*(0.1875) + 12 = 12.5626

And the height is in feet, then the maximum height is 12.5626 ft

6 0

3 years ago