Given: f(x)=1-x^2,g(x)=1-2x, and h(x)= 1/x^2+1 find f(g(a+1)) find g(1/h(z))
1 answer:
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Actually Welcome to the Concept of the Inverse of real function.
Let's consider here, g(n) = y ,
so we get as,
no, cubing the power both side we get as,
=>
now,
so finally, we get as,
=>
hence,here, n = inverse of the g(n) function.
so,
g^-1 (n) = 2y^3+1.
Answer:
<h2>Answer with explanation:</h2>
We are asked to prove by the method of mathematical induction that:
where n is a positive integer.
- Let us take n=1
then we have:
Hence, the result is true for n=1.
- Let us assume that the result is true for n=k
i.e.
- Now, we have to prove the result for n=k+1
i.e.
<u>To prove:</u>
Let us take n=k+1
Hence, we have:
( Since, the result was true for n=k )
Hence, we have:
Also, we know that:
(
Since, for n=k+1 being a positive integer we have:
)
Hence, we have finally,
Hence, the result holds true for n=k+1
Hence, we may infer that the result is true for all n belonging to positive integer.
i.e.
where n is a positive integer.