Answer:
Step-by-step explanation:
Given that events A1, A2 and A3 form a partiton of the sample space S with probabilities P(A1) = 0.3, P(A2) = 0.5, P(A3) = 0.2.
i.e. A1, A2, and A3 are mutually exclusive and exhaustive
E is an event such that
P(E|A1) = 0.1, P(E|A2) = 0.6, P(E|A3) = 0.8,




Answer: 0.8031
Step-by-step explanation:
Binomial distribution:
For a binomial variable x,
The probability of getting success in x trials = 
, where n = Total trials .
p= Probability of getting success in each trial.
For the given situation , we take x as the number of damaged apple .
Given : The proportion of damaged apples : p=0.15
n= 10
Then, the probability that his sample will contain at least one damaged apple. :-

Hence, the required probability = 0.8031
Step-by-step explanation:



Option → D
Step-by-step explanation:
x³.y =(5)³.(10)
=1250