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kiruha [24]
3 years ago
8

. Bobignment In what year was the LAWMA Established-​

Mathematics
1 answer:
Lisa [10]3 years ago
7 0
1977. All that took was a 3 second search...
You might be interested in
How do three planes intersect at one point?
natima [27]
Imagine a corner of a cube.
It is made of three planes interesting at a single point
The image should help.

7 0
3 years ago
Can some help me out with this EXTRA POINTS!!
Butoxors [25]

Answer: ≈ 185.73009

Step-by-step explanation:

area of square: length^{2}

area of circle: \frac{radius^{2} * \pi }{y}

length: 15

radius = diameter/2

radius: 5

area of square - area of circle =  area between square and circle:

15^{2} - \frac{5^{2} * \pi }{2} = 225 - \frac{25\pi}{2} ≈ 185.73009

hope it helps!

Please mark as brainliest.

8 0
2 years ago
Verify that 2,-1 and 1⁄2 are the zeroes of the cubic polynomial
Mariulka [41]

Answer:

i) Since P(2), P(-1) and P(½) gives 0, then it's true that 2,-1 and 1⁄2 are the zeroes of the cubic polynomial.

ii) - the sum of the zeros and the corresponding coefficients are the same

-the Sum of the products of roots where 2 are taken at the same time is same as the corresponding coefficient.

-the product of the zeros of the polynomial is same as the corresponding coefficient

Step-by-step explanation:

We are given the cubic polynomial;

p(x) = 2x³ - 3x² - 3x + 2

For us to verify that 2,-1 and 1⁄2 are the zeroes of the cubic polynomial, we will plug them into the equation and they must give a value of zero.

Thus;

P(2) = 2(2)³ - 3(2)² - 3(2) + 2 = 16 - 12 - 6 + 2 = 0

P(-1) = 2(-1)³ - 3(-1)² - 3(-1) + 2 = -2 - 3 + 3 + 2 = 0

P(½) = 2(½)³ - 3(½)² - 3(½) + 2 = ¼ - ¾ - 3/2 + 2 = -½ + ½ = 0

Since, P(2), P(-1) and P(½) gives 0,then it's true that 2,-1 and 1⁄2 are the zeroes of the cubic polynomial.

Now, let's verify the relationship between the zeros and the coefficients.

Let the zeros be as follows;

α = 2

β = -1

γ = ½

The coefficients are;

a = 2

b = -3

c = -3

d = 2

So, the relationships are;

α + β + γ = -b/a

αβ + βγ + γα = c/a

αβγ = -d/a

Thus,

First relationship α + β + γ = -b/a gives;

2 - 1 + ½ = -(-3/2)

1½ = 3/2

3/2 = 3/2

LHS = RHS; So, the sum of the zeros and the coefficients are the same

For the second relationship, αβ + βγ + γα = c/a it gives;

2(-1) + (-1)(½) + (½)(2) = -3/2

-2 - 1½ + 1 = -3/2

-1½ - 1½ = -3/2

-3/2 = - 3/2

LHS = RHS, so the Sum of the products of roots where 2 are taken at the same time is same as the coefficient

For the third relationship, αβγ = -d/a gives;

2 * -1 * ½ = -2/2

-1 = - 1

LHS = RHS, so the product of the zeros(roots) is same as the corresponding coefficient

7 0
3 years ago
What is 3=7(4 - 2u)-6u
alisha [4.7K]

Answer:

u = 5/4

Step-by-step explanation:

to evaluate for the value of u we would simply open the bracket and then evaluate for the value of u by collecting the like terms together.

solution

3=7(4 - 2u)-6u

3 = 28- 14u - 6u

collect the like terms

3 + 14u + 6u = 28

20u = 28 - 3

20u = 25

divide both sides by the coefficient of u which is 20

20u/20 = 25/20

u = 5/4

5 0
3 years ago
Read 2 more answers
What is -6x+3(4x-5)=21
Fynjy0 [20]
-15 i think if not u just got to use the quadratic formula.
5 0
3 years ago
Read 2 more answers
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