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kiruha [24]
3 years ago
8

. Bobignment In what year was the LAWMA Established-​

Mathematics
1 answer:
Lisa [10]3 years ago
7 0
1977. All that took was a 3 second search...
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Need help ASAP, I do not understand this one.
taurus [48]
2y+20=100
2y=80
y=40

The explanation for this would because because the two base angles of an isosceles triangle are equal so since the both equal to 40 degrees, in total would be 80 degrees.

Since the total degrees of a triangle is 180 and you know the base angles make up for 80 percent you subtract that from the total of the angle your trying to find, which is 2y+20.
6 0
3 years ago
Read 2 more answers
Does each equation represent exponential decay or exponential growth?
lisov135 [29]

Answer:

1. H = 5.9(0.82)^{t}. Exponential decay function.

2. y = 0.8(3.6)^{t}. Exponential growth function.

3. f(t) = 0.72(15)^{t}. Exponential growth function.

4. A = \frac{4}{9} (8)^{t}. Exponential growth function.

5. A = (\frac{4}{3})^{t}. Exponential growth function.

6.  H = \frac{7}{2} (\frac{5}{6} )^{t}. Exponential decay function.

7. g(x) = 0.3(x). Not an exponential function.

Step-by-step explanation:

1. H = 5.9(0.82)^{t}. This is an exponential decay function.

As the value of t increases H-value decreases.

2. y = 0.8(3.6)^{t}. This is an exponential function of growth.

As the value of t increases y-value also increases.

3. f(t) = 0.72(15)^{t}. This is an another example of exponential growth function.

As the value of t increases f(t)-value also increases.

4. A = \frac{4}{9} (8)^{t}. This is again an example of exponential growth function.

As the value of t increases A-value also increases.

5. A = (\frac{4}{3})^{t}. This is again an example of exponential growth function.

As the value of t increases A-value also increases.

6. H = \frac{7}{2} (\frac{5}{6} )^{t}. This is another an example of exponential decay function.

As the value of t increases, H-value decreases.

7. g(x) = 0.3(x). This is a non-exponential function. (Answer)

4 0
4 years ago
Divide the following polynomial using synthetic division, then place the answer in the proper location on the grid. Write answer
MAXImum [283]
-4 1. -8. 24. 12. 40 -4. 48. -288. 1104 1 -12. 72. -276. R1144 ANSWER: X^3-12x^2+72x-276+1144/x+4
8 0
3 years ago
Read 2 more answers
If (z°z)(x)=1/16x , what is z (x)?
vivado [14]
<span>assume z = ax for simplicity z(z) = a(ax) = a^2x let a^2x = 1/16x and solve for a </span>
6 0
4 years ago
In a string of 12 Christmas tree light bulbs, 3 are defective. The bulbs are selected at random and tested, one at a time, until
Juliette [100K]

Using the hypergeometric distribution, it is found that there is a 0.0273 = 2.73% probability that the third defective bulb is the fifth bulb tested.

In this problem, the bulbs are chosen without replacement, hence the <em>hypergeometric distribution</em> is used to solve this question.

<h3>What is the hypergeometric distribution formula?</h3>

The formula is:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • N is the size of the population.
  • n is the size of the sample.
  • k is the total number of desired outcomes.

In this problem:

  • There are 12 bulbs, hence N = 12.
  • 3 are defective, hence k = 3.

The third defective bulb is the fifth bulb if:

  • Two of the first 4 bulbs are defective, which is P(X = 2) when n = 4.
  • The fifth is defective, with probability of 1/8, as of the eight remaining bulbs, one will be defective.

Hence:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}

P(X = 2) = h(2,12,4,3) = \frac{C_{3,2}C_{9,1}}{C_{12,4}} = 0.2182

0.2182 x 1/8 = 0.0273.

0.0273 = 2.73% probability that the third defective bulb is the fifth bulb tested.

More can be learned about the hypergeometric distribution at brainly.com/question/24826394

8 0
2 years ago
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