All categories

3 years ago

Solve the equation sin theta = 0.3 to the nearest tenth. Use the restrictions 90degrees < theta < 180degrees.

1 answer:

5 0

We first do:
∅ = sin⁻¹(0.3)
∅ = 17.5°

To go into the second quadrant, we add 90°.
∅ = 17.5 + 90
= 107.5°
The answer is A.

You might be interested in

WILL GIVE BRAINLIEST TO CORRECT ANSWER(S)

elena55 [62]

Answer:

A: The correlation coefficient is a statistical measure of the strength of the relationship between the relative movements of two variables. The values range between -1.0 and 1.0. A calculated number greater than 1.0 or less than -1.0 means that there was an error in the correlation measurement.

B: he correlation coefficient is a statistical calculation that is used to examine the relationship between two sets of data. The value of the correlation coefficient tells us about the strength and the nature of the relationship. Correlation coefficient values can range between +1.00 to -1.00.

Step-by-step explanation:

Hopefully this helped!!!

7 0

3 years ago

Data set: 47, 45, 44, 41, 48

Tamiku [17]

Answer:

Step-by-step explanation:

3 0

2 years ago

Someone please help me

Usimov [2.4K]

Yes 1 and 3 are supplementary

4 0

3 years ago

Read 2 more answers

An=an-1+6an-2 n>2 a0=3 a1=6

Svetach [21]

$\begin{cases}a_0=3\\a_1=6\\a_n=a_{n-1}+6a_{n-2}&\text{for }n>2\end{cases}$

Let the generating function for $a_n$ be

$A(x)=\displaystyle\sum_{n\ge0}a_nx^n$

Multiplying both sides by $x^{n-2}$

$a_nx^{n-2}=a_{n-1}x^{n-2}+6a_{n-2}x^{n-2}$

Summing both sides over the non-negative integers greater than or equal to 2 gives

$\displaystyle\sum_{n\ge2}a_nx^{n-2}=\sum_{n\ge2}a_{n-1}x^{n-2}+6\sum_{n\ge2}a_{n-2}x^{n-2}$
$\displaystyle\frac1{x^2}\sum_{n\ge2}a_nx^n=\frac1x\sum_{n\ge1}a_nx^n+6\sum_{n\ge0}a_nx^n$
$\displaystyle\frac1{x^2}\left(\sum_{n\ge0}a_nx^n-a_0-a_1x\right)=\frac1x\left(\sum_{n\ge0}a_nx^n-a_0\right)+6\sum_{n\ge0}a_nx^n$
$\displaystyle\frac1{x^2}\left(A(x)-3-6x\right)=\frac1x\left(A(x)-3\right)+6A(x)$
$A(x)=\dfrac{3x+3}{1-x-6x^2}$
$A(x)=\dfrac3{5(1+2x)}+\dfrac{12}{5(1-3x)}$

For $|x|$ , the two series converge to

$\displaystyle A(x)=\frac35\sum_{n\ge0}(-2x)^n+\frac{12}5\sum_{n\ge0}(3x)^n$
$\implies A(x)=\displaystyle\sum_{n\ge0}\dfrac{3(-2)^n+12(3)^n}5x^n$
$a_n=\dfrac{3(-2)^n+12(3)^n}5=\dfrac{3(-2)^n+4(3)^{n+1}}5$

5 0

3 years ago

What is the probability that x is between $34 and $38?

Elina [12.6K]

What is the probability that the stock price will be between $34 and $38? d. Determine the ... A random variable X is uniformly distributed between 45 and 150.

8 0

3 years ago