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2 years ago

._. ._.

Mathematics

1 answer:

astra-53 [7]2 years ago

6 0

9514 1404 393

Answer:

(x, y) = (0, -26)

Step-by-step explanation:

The y-intercept is the y-value that corresponds to x=0. Here, we have a table that has x-values that differ by 12 and 24. We want to find the y-value that corresponds to an x-value 24 less than the lowest one on the table:

24 -24 = 0

We notice that when x-values differ by 24, the y-values differ by 10 -(-8) = 18. So, the y-value we want is 18 less than the lowest one in the table:

y = -8 -18 = -26

The (x, y) coordinates of the y-intercept are (0, -26).

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(Look at picture above) Find the volume of the cone. Round your answer to the nearest tenth. 9 yd 7 yd The volume of the cone is

nata0808 [166]

Answer:

V = 115.5 cubic yards

Step-by-step explanation:

V (cone) = 1/3πr²h

just substitute given values to get:

r = 7/2 or 3.5

h = 9

V = π(3.5²)(9)/3

V = 115.5 cubic yards

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2 years ago

A pole that is 2.5 m tall casts a shadow that is 1.47 m long. At the same time, a nearby tower casts a shadow that is 36.25 m lo

Roman55 [17]

The tower is 61.65 meters tall.

<u>SOLUTION: </u>

Given that, a pole that is 2.5 m tall casts a shadow that is 1.47 m long.

At the same time, a nearby tower casts a shadow that is 36.25 m long.

We have to find height of the tower.

Now, we know that,

$2.5 \mathrm{m} \text { tall } \rightarrow 1.47 \text { long shadow }$

Then, (let it be) n meter tall $\rightarrow$ 36.25 long shadow

So, by cross multiplication method,

$\Rightarrow \frac{2.5}{1.47}=\frac{n}{36.25}$

This can be written as,

$\Rightarrow 36.25 \times 2.5=1.47 \times n \rightarrow 1.47 n=90.625 \rightarrow n=61.649 \rightarrow n=61.65 \text{ m}$

Cross multiplications steps: (To find Single Variable)

Multiply the numerator of the left-hand fraction by the denominator of the right-hand fraction.
Multiply the numerator of the right-hand fraction by the denominator of the left-hand fraction.
Set the two products equal to each other.
Solve for the variable.

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Answer:

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Hi student, let me help you out! :)