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Andreas93 [3]
2 years ago
9

If a /b=p/q, then (a + b)/b= b/(a+d)

Mathematics
1 answer:
liberstina [14]2 years ago
5 0

If a /b = p/q, then (a + b)/b = b/(a+d) exists FALSE.

<h3>What is Componendo Property of fractions?</h3>

Let a, b, c, d be the four numbers, then

if a : b = c : d then (a + b) : b :: (c + d) : d.

If a : b :: c : d then (a - b) : b :: (c - d) : d.

Given equation,

$\Rightarrow \frac{a}{b}=\frac{p}{q}$$

Adding 1 on both sides of the equation, we get

$&\Rightarrow \frac{a}{b}+1=\frac{p}{q}+1 \\

$&\Rightarrow \frac{a+b}{b}=\frac{p+q}{q}

This rule exists also comprehended as the Componendo property of fractions.

Therefore, $\frac{a+b}{b}=\frac{p+q}{q}$$ then a = pb + q but the hypothesis says that

a = (p+b) / q.

If a /b = p/q, then (a + b)/b = b/(a+d) exists FALSE.

To learn more about the Componendo property of fractions refer to:

brainly.com/question/2933117

#SPJ9

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How do I solve this, and what is the answer? please and thank you.
vovangra [49]

Answer:

A. (x +8) + (-4x+31)/(x^2+2x+1)

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This fact eliminates all but choices A and C.

The denominator of the remainder term is the denominator of the original expression, so will be x^2 +2x +1, as shown in choice A.

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This is a polynomial long division problem. It is worked in virtually the same way that numerical long division problems are worked: first you find a quotient term, then you multiply that by the divisor and subtract the result from the dividend. The difference is the new dividend. These steps are identical to numerical long division.

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As mentioned above, the quotient term is computed only from the highest-degree terms of dividend and divisor, so that part is actually simpler than for numerical long division.

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murzikaleks [220]

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I am joyous to assist you anytime.

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