23) m 2 = 7x + 670°

Mathematics

1 answer:

lakkis [162]4 years ago

3 0

Answer:

∠2 = 55°

Step-by-step explanation:

Given that the triangle has 2 congruent sides then the triangle is isosceles.

Thus the 2 base angle are congruent, both equal to ∠2

The sum of the 3 angles in a triangle = 180

7x + 6 + 7x + 6 + 70 = 180, that is

14x + 82 = 180 ( subtract 82 from both sides )

14x = 98 ( divide both sides by 14 )

x = 7

Hence

∠2 = 7x + 6 = (7 × 7) + 6 = 49 + 6 = 55°

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Given the circle with the equation (x - 3)2 + y2 = 49, determine the location of each point with respect to the graph of the cir

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To find out if a point is inside, on, or outside a circle, we need to substitute the ordered pair into the equation of the circle:
(x-xc)^2+(y-yc)^2=r^2
where (xc,yc) is the centre of the circle, and r=radius of the circle.

If the left-hand side [(x-xc)^2+(y-yc)^2] is less than r^2, then point (x,y) is INSIDE the circle. If the left-hand side is equal to r^2, the point is ON the circle.
Finally, if the left-hand side is greater than r^2, the point is OUTSIDE the circle.

For the given problem, we have xc=3, yc=0, or centre at (3,0), r=sqrt(49)=7
(x-xc)^2+(y-yc)^2=r^2 => (x-3)^2+y^2=7^2

A. (-1,1),
(x-3)^2+y^2=7^2 => (-1-3)^2+1^2=16+1=17 <49 [inside circle]

B. (10,0)
(x-3)^2+y^2=7^2 => (10-3)^2+0^2=49+0=49 [on circle]

C. (4,-8)
(x-3)^2+y^2=7^2 => (4-3)^2+(-8)^2=1+64=65 > 49 [outside circle]