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2 years ago

9

Hello help me plsss plssss pretty pleasee!!!

2 answers:

Gala2k [10]2 years ago

8 0

Answer:6.1638 7.69 8.18.04

Step-by-step explanation:

Radda [10]2 years ago

8 0

6. 1638

7. 20

8. 9 4/12 or 9 1/3 (simplified)

Hope this helps!! :D may i have brainliest please?

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Increase 220 by 15% please

rjkz [21]

Lets do this step by step.

1st.) what is 15% as a decimal
15% = 0.15

2nd.) multiply
220 x 0.15 = 33

3rd) we add that 33 and 220 since this its asking for the increase
220 + 33 = 253

Answer = 253

6 0

2 years ago

9(x) = 2x-1<br> r(x) = -2x<br> 2<br> 2<br> Find the value of r(q (2)).

BabaBlast [244]

Answer:

<em>Answer</em><em> </em><em>is</em><em> </em><em>-6</em>

Step-by-step explanation:

$given \: q(x) = 2x - 1 \\ and \: r(x) = - 2x \\ r(q(2)) = r(2(2) - 1) \\ \: \: = r(4 - 1) \\ = r(3) \\ = - 2(3) \\ = - 6 \\ therefore \: r(q(2)) = - 6$

<em>HAVE A NICE DAY</em><em>!</em>

<em>THANKS FOR GIVING ME THE OPPORTUNITY</em><em> </em><em>TO ANSWER YOUR QUESTION</em><em>. </em>

6 0

2 years ago

Which describes the calculations that could be used to solve this problem?

Darya [45]

Answer:

A.

Subtract 37 – 13. Then divide the difference by 4.

Step-by-step explanation:

After the box:

37 - 13 left

No. of bags:

(37 - 13)/4

4 0

3 years ago

Lisa uses her hair dryer daily dryer uses 1500 watts. it take 10 mintes to dry her hair each time she uses it. how much would it

Volgvan

Answer:

Step-by-step explanation:

The answer is $11.55 for the week.

1) Since 1 watt is 0.001 kilowatts, 1500 watts is 1.5 kilowatts.

2) Multiply that by 7 for the week and that equals 10.5.

3) It takes her 10 minutes each day, so it takes 70 minutes per week, that is also 1.1 hours.

4) Multiply 10.5 kilowatts by 1.1 hours and you get 11.55.

5) The answer is $11.55 per week to dry Lisa's hair.

3 0

2 years ago

Please help with this and explain how to do it, I'll give 15 points

MrRissso [65]

Answer:

Option (4).

Step-by-step explanation:

Outer diameter of the hollow metallic ball = 10 centimeters

Outer radius of this ball = $\frac{10}{2}$ = 5 cm

Volume of the outer ball $V_{1}$ = $\frac{4}{3}\pi (r)^3$

= $\frac{4}{3}\pi (5)^3$

Inner radius of the hollow metallic ball = (5 - 1) = 4 cm

Volume of the inner hollow ball $V_{2}$ = $\frac{4}{3}\pi (4)^3$

Volume of the metal used in the metallic ball = $V_{1}-V_{2}$

= $\frac{4}{3}\pi (5)^3-\frac{4}{3}\pi (4)^{3}$

= $\frac{4}{3}\pi [(5)^3-(4)^3]$

Therefore, expression given in option (4) will be used to measure the volume of the hollow metallic ball.

8 0

2 years ago