Question

Let g(x)=2x and h(x)=x^2+4 find the value (goh)(0)

Answer 1

(goh)=g(h(x))
h(0)=0^2+4=4
g(4)=8
(goh)(0)=8

Answer 2

ANSWER

$(g \circ \: h)(0) = 8$

EXPLANATION

The given function

$g(x) = 2x$
$h(x) = {x}^{2} + 4$

We want to find the composition of the function,

$(g \circ \: h)(x) = g(h(x))$

$(g \circ \: h)(x) = 2({x}^{2} + 4)$

$(g \circ \: h)(x) = 2{x}^{2} + 8$

We substitute

$x = 0$

to obtain,

$(g \circ \: h)(0) = 2({0})^{2} + 8$

This will simplify to,

$(g \circ \: h)(0) = 8$