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n200080 [17]
3 years ago
14

Let g(x)=2x and h(x)=x^2+4 find the value (goh)(0)

Mathematics
2 answers:
k0ka [10]3 years ago
4 0
(goh)=g(h(x))
h(0)=0^2+4=4
g(4)=8
(goh)(0)=8
iogann1982 [59]3 years ago
3 0
ANSWER

(g \circ \: h)(0) = 8

EXPLANATION

The given function

g(x) = 2x
h(x) = {x}^{2} + 4

We want to find the composition of the function,

(g \circ \: h)(x) = g(h(x))

(g \circ \: h)(x) = 2({x}^{2} + 4)

(g \circ \: h)(x) = 2{x}^{2} + 8

We substitute

x = 0

to obtain,

(g \circ \: h)(0) = 2({0})^{2} + 8

This will simplify to,

(g \circ \: h)(0) = 8
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