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Neporo4naja [7]
2 years ago
6

In 2010, there were approximately 6 million girls living in Orange City. In 2011, the population was down to 4 million girls. Ho

w many girls lived in Orange City in 2011 in comparison to 2010? Write your answer in scientific notation.
Mathematics
1 answer:
Colt1911 [192]2 years ago
4 0

Answer:2010 +2011+2010=6021

6+4 =11

Step-by-step explanation:add then you divide

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Colby worked three more hours on tuesday than he did on monday. on wednesday, he worked one hour more than twice the number of h
bulgar [2K]
Monday = X
Tuesday = X + 3 (Problem says three more hours than he worked on Monday)
Wednesday = 2x + 1
(Problem says he worked 1 hour more than two times the number of hours on monday) 
This side of the equation would be - 
X + (X +3) + (2X + 1) 
That's monday plus tuesday plus wednesday. 
Then you would set up the other side of the equation. 
This would be the total number of hours so it would be equal to monday, tuesday and wednesday combined. 
2 + (5x) 
Two hours more than five times the amount of Monday (X) 

Now we put this together to have an equation 
X + (X + 3) + (2x+ 1) = 2 + 5x 
Now we need to collect like terms
4x + 4 = 2 + 5x 
I just simplified the left side of the equation
Now I will subtract 4x from the left side to get all the variables on one side 
4 = 2 + x 
Now I subtract 2 to get the numbers both on one side
2 = x 
So, Colby worked 2 hours on Monday.
6 0
3 years ago
Draw 8 lines that are between 1 inch and 3 inches long. Measure each line to the nearest fourth inch, and make a line plot
ELEN [110]
Just ADD 1 +3 then subtract it from 1.4 inch
8 0
3 years ago
Polar form of (x+6)^2 +y^2=36
Sindrei [870]

Answer:

  r = -12cos(θ)

Step-by-step explanation:

The usual translation can be used:

  • x = r·cos(θ)
  • y = r·sin(θ)

Putting these relationships into the formula, we have ...

  (r·cos(θ) +6)² +(r·sin(θ))² = 36

  r²·cos(θ)² +12r·cos(θ) +36 +r²·sin(θ)² = 36

  r² +12r·cos(θ) = 0 . . . . subtract 36, use the trig identity cos²+sin²=1

  r(r +12cos(θ)) = 0

This has two solutions for r:

  r = 0 . . . . . . . . a point at the origin

  r = -12cos(θ) . . . the circle of interest

4 0
3 years ago
Please help with #6 need it very soon
gregori [183]

Answer:

If this is a proof then here is the answer.

Angle ABD is Congruent to Angle CBD = Given

Angle BDA is Congruent to Angle BDC = Given

Angle ABD is Congruent to Angle CBD = Definition of Angle Bisector

Line Segment BD is Congruent to Line Segment BD = Reflexive Property

Line Segment AB is Congruent to Linge Segment CB = Angle-Side-Angle or ASA

Step-by-step explanation:

Lucky for you, I just learned this also ;)


Since you are given your first two directions, put them down as GIVEN in the proof.

Next, Since ABD and CBD are congruent angles, you can assume that it is an angle bisector since angle bisectors always bisect equally.

Then, (This one is obvious), since Line Segment BD shares a side with itself, it is equal by the Reflexive Property (EX: AB is congruent to AB).

Finally, Since there is two angles with a congruent side in the middle, you can confirm that it is equal by Angle-Side-Angle.

Hope this helped!


5 0
3 years ago
Write this as an equation, then solve.
ANTONII [103]
19.5 in difference 
difference indicates that you'll be subtracting so 29 3/4 - 10 1/4 = 19.5

3 0
3 years ago
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