Answer:
This should be parallel.
Step-by-step explanation:
Two lines are said to be parallel only if their slope matches. They are said to be perpendicular only if the slopes are negative reciprocals.
Here, you should put both equations in slope intercept form which is y=mx+b. The letter "M" represents the slope of both equations.
2y-6=3x+4 turns into 2y=3x+10 after adding 6 and into y=3/2x+5 after dividing the equation by 2. The slope for this equation is 3/2.
8y=12x+8 must be divided by 8 to be in slope intercept form. This equation becomes y=3/2x+1. Here the slope is also 3/2.
The slopes for each equation match making these lines parallel.
If Jimmy ate 6 of them, 6 of them are gone.
g= the number of raisins he started out with
g-6 <--- the answer
"B" is the answer.
I hope this helps!
~kaikers
Answer:
bottom side (a) = 3.36 ft
lateral side (b) = 4.68 ft
Step-by-step explanation:
We have to maximize the area of the window, subject to a constraint in the perimeter of the window.
If we defined a as the bottom side, and b as the lateral side, we have the area defined as:

The restriction is that the perimeter have to be 12 ft at most:

We can express b in function of a as:

Then, the area become:

To maximize the area, we derive and equal to zero:

Then, b is:

The answer is C 2/5 = 0.4
76766 is the correct answer