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3 years ago

A green cross is formed by placing two rectangles of dimensions 8cm×4cm over

Mathematics

1 answer:

Goshia [24]3 years ago

4 0

Answer:

The perimeter of the green cross is 32 cm

Step-by-step explanation:

Perimeter

It's the sum of all the external side lengths of a given shape.

The green cross formed by two rectangles is shown in the figure below.

We have outlined the dimensions of the external sides of the resulting cross.

Note there are four corners of 2 cm by 2 cm and four sides of 4 cm each.

The total perimeter is:

8 * 2 cm + 4 * 4 cm = 16 cm + 16 cm = 32 cm

The perimeter of the green cross is 32 cm

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Calculate the sample standard deviation and sample variance for the following frequency distribution of hourly wages for a sampl

lidiya [134]

Answer:

(a) The sample variance is 16.51

(a) The sample standard deviation is 4.06

Step-by-step explanation:

Given

$\begin{array}{cc}{Class} & {Frequency} & 8.26 - 10.00 & 20 &10.01-11.75 & 38 &11.76 - 13.50& 36 & 13.51-15.25 &25&15.26-17.00 &27 &\ \end{array}$

Solving (a); The sample variance.

First, calculate the class midpoints.

This is the mean of the intervals.

i.e.

$x_1 = \frac{8.26+10.00}{2} = \frac{18.26}{2} = 9.13$

$x_2 = \frac{10.01+11.75}{2} = \frac{21.76}{2} = 10.88$

$x_3 = \frac{11.76+13.50}{2} = \frac{25.26}{2} = 12.63$

$x_4 = \frac{13.51+15.25}{2} = \frac{28.76}{2} = 14.38$

$x_5 = \frac{15.26+17.00}{2} = \frac{32.26}{2} = 16.13$

So, the table becomes:

$\begin{array}{ccc}{Class} & {Frequency} & {x} & 8.26 - 10.00 & 20&9.13 &10.01-11.75 & 38 &10.88&11.76 - 13.50& 36 &12.63& 13.51-15.25 &25&14.38&15.26-17.00 &27 &16.13\ \end{array}$

Next, calculate the mean

$\bar x = \frac{\sum fx}{\sum f}$

$\bar x = \frac{20*9.13 + 38 * 10.88+36*12.63+25*14.38+27*16.13}{20+38+36+25+27}$

$\bar x = \frac{1845.73}{146}$

$\bar x = 12.64$

Next, the sample variance is:

$\sigma^2 = \frac{\sum f(x - \bar x)^2}{\sum f - 1}$

So, we have:

$\sigma^2 = \frac{20*(9.13-12.63)^2 + 38 * (10.88-12.63)^2 +...........+27 * (16.13 -12.63)^2}{20+38+36+25+27-1}$

$\sigma^2 = \frac{2393.6875}{145}$

$\sigma^2 = 16.51$

The sample standard deviation is:

$\sigma = \sqrt{\sigma^2}$

$\sigma = \sqrt{16.51}$

$\sigma = 4.06$

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2 years ago

1.09 g/mL to lbs/gal

julia-pushkina [17]

It'd be 9.096491 hope that helps.

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3 years ago

Janet received the following grades in an accounting class at McClenan Community College: 65, 80, 70, 100, 75, and 90. The instr

Agata [3.3K]

70+75+80+90+100=415
415/5=83
After the lowest grade is dropped, Janet's average would be an 83%

6 0

3 years ago

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alexira [117]

Answer:

it would be in the fourth quadrant, directly underneath where it is now. the base would be c and d

5 0

3 years ago

Johnny's mother has 3 children. The first child is named April. The second child is named May. What is the third child's name

Musya8 [376]

The answer is Johnny. You can conclude from the first sentence of your question. It is stating that Johnny's mother has three children. Johnny is included in the three children. So, the third child's name was Johnny!
Thank you! :D

3 0

3 years ago