Find the slope of the line that contains the points named. G(3, -2), H(7, -2)

Mathematics

2 answers:

Sati [7]3 years ago

6 0

Answer:

Step-by-step explanation:

To find the slope

m= ( y2-y1)/(x2-x1)

= ( -2 - -2)/ ( 7-3)

= (-2+2)/(7-3)

= 0/4

jarptica [38.1K]3 years ago

5 0

A. 0

Answer:

Solution given

(x1,y1)=G(3, -2),

(x2,y2)=H(7, -2)

now

slope=(y2-y1)/(x2-x1)=(-2+2)/(7-3)=0/4=0

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3 years ago

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Flura [38]

Answer:

$y = -\frac{1}{3}x-2$

Step-by-step explanation:

From the table it is clear that the line is passing through the points $(0,\: -2)= (x_1, \:y_1) \: \&\: (-6, \:0)=(x_2,\:y_2)$

(There are many other points in the table and any two of them can chosen as per our convenience)

Equation of line in two point form is given as:

$\frac{y-y_1}{y_1 - y_2} = \frac {x-x_1}{x_1 - x_2} \\\\\therefore \frac{y-(-2)}{-2 - 0} = \frac {x-0}{0 - (-6)} \\\\\therefore \frac{y+2}{-2} = \frac {x}{0+6)} \\\\\therefore \frac{y+2}{-2} = \frac {x}{6)} \\\\\therefore 6(y + 2) = - 2(x)\\\therefore 6y + 12 = - 2x \\\therefore 6y = - 2x - 12\\\\\therefore y = -\frac{2}{6}x-\frac{12}{6}\\\\\huge \red {\boxed {y = -\frac{1}{3}x-2}} \\\\$