All categories

4 years ago

Write 5.8 as a mixed number in simplest form

Mathematics

2 answers:

FinnZ [79.3K]4 years ago

4 0

5 8/10 which can be simplified as 5 4/5 because 8 & 10 share the common factor of 2. So the answer is 5 4/5.

frutty [35]4 years ago

3 0

I believe it is 5 4/5

You might be interested in

What is the value of x?

Gala2k [10]

Answer:

I just did the quiz and got it right. The answer is 68. Hope this helps :)

Step-by-step explanation:

6 0

3 years ago

How many times will lines 3x+4y=8 and y-5x=2 intersect

nlexa [21]

They will intersect once at points (0,2). Hope it helps

8 0

3 years ago

Order the following decimals from greatest to least <br> 0.25 0.67 0.8 0.5 0.33

Lesechka [4]

Step-by-step explanation:

0.8, 0.5, 0.67, 0.33, 0.25

4 0

3 years ago

How is multiplication related to addition ?

Phantasy [73]

U need numbers for both

8 0

3 years ago

Read 2 more answers

The graph of an inverse trigonometric function passes through the point (1, pi/2). Which of the following could be the equation

rodikova [14]

Answer: C) $y=sin^-1 x$

Step-by-step explanation:

Since, the graph of an inverse trigonometric function will pass through the point $(1,\frac{\pi}{2})$ ,

If this point satisfies the function,

For the function $y=cos^{-1} x$

If x = 1

$y=cos^{-1}1=0$

Thus, $(1,\frac{\pi}{2})$ is not satisfying function $y=cos^{-1} x$ ,

⇒ The graph of $y=cos^{-1} x$ is not passing through the point $(1,\frac{\pi}{2})$

For the function $y=cot^{-1}x$

If x = 1

$y=cot^{-1}1=\frac{\pi}{4}$

Thus, $(1,\frac{\pi}{2})$ is not satisfying function $y=cot^{-1}x$ ,

⇒ The graph of $y=cot^{-1}x$ is not passing through the point $(1,\frac{\pi}{2})$

For the function $y=sin^{-1} x$

If x = 1

$y=sin^{-1}1=\frac{\pi}{2}$

Thus, $(1,\frac{\pi}{2})$ is satisfying function $y=sin^{-1} x$ ,

⇒ The graph of $y=sin^{-1} x$ is passing through the point $(1,\frac{\pi}{2})$ .

For the function $y=tan^{-1}x$

If x = 1

$y=tan^{-1}1=\frac{\pi}{4}$

Thus, $(1,\frac{\pi}{2})$ is not satisfying function $y=cos^{-1} x$ ,

⇒ The graph of $y=tan^{-1} x$ is not passing through the point $(1,\frac{\pi}{2})$ .

Hence, Option C is correct.

3 0

3 years ago