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3 years ago

15

Can someone answer this for me

1 answer:

DochEvi [55]3 years ago

7 0

Answer: x=2.5

y=-1.75

Step-by-step explanation:

x-2y=6

x=6+2y

3(6+2y)+2y=4

18+6y+2y=4

8y=-14

y=-1.75

x=6+(-1.75)(2)

x=2.5

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Write a division expression that matches the situation.

Lemur [1.5K]

half a yard of ribbon divided by seven i think

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3 years ago

Read 2 more answers

Suppose a random variable x is best described by a uniform probability distribution with range 22 to 55. Find the value of a tha

const2013 [10]

Answer:

(a) The value of <em>a</em> is 53.35.

(b) The value of <em>a</em> is 38.17.

(c) The value of <em>a</em> is 26.95.

(d) The value of <em>a</em> is 25.63.

(e) The value of <em>a</em> is 12.06.

Step-by-step explanation:

The probability density function of <em>X</em> is:

$f_{X}(x)=\frac{1}{55-22}=\frac{1}{33}$

Here, 22 < X < 55.

(a)

Compute the value of <em>a</em> as follows:

$P(X\leq a)=\int\limits^{a}_{22} {\frac{1}{33}} \, dx \\\\0.95=\frac{1}{33}\cdot \int\limits^{a}_{22} {1} \, dx \\\\0.95\times 33=[x]^{a}_{22}\\\\31.35=a-22\\\\a=31.35+22\\\\a=53.35$

Thus, the value of <em>a</em> is 53.35.

(b)

Compute the value of <em>a</em> as follows:

$P(X< a)=\int\limits^{a}_{22} {\frac{1}{33}} \, dx \\\\0.95=\frac{1}{33}\cdot \int\limits^{a}_{22} {1} \, dx \\\\0.49\times 33=[x]^{a}_{22}\\\\16.17=a-22\\\\a=16.17+22\\\\a=38.17$

Thus, the value of <em>a</em> is 38.17.

(c)

Compute the value of <em>a</em> as follows:

$P(X\geq a)=\int\limits^{55}_{a} {\frac{1}{33}} \, dx \\\\0.85=\frac{1}{33}\cdot \int\limits^{55}_{a} {1} \, dx \\\\0.85\times 33=[x]^{55}_{a}\\\\28.05=55-a\\\\a=55-28.05\\\\a=26.95$

Thus, the value of <em>a</em> is 26.95.

(d)

Compute the value of <em>a</em> as follows:

$P(X\geq a)=\int\limits^{55}_{a} {\frac{1}{33}} \, dx \\\\0.89=\frac{1}{33}\cdot \int\limits^{55}_{a} {1} \, dx \\\\0.89\times 33=[x]^{55}_{a}\\\\29.37=55-a\\\\a=55-29.37\\\\a=25.63$

Thus, the value of <em>a</em> is 25.63.

(e)

Compute the value of <em>a</em> as follows:

$P(1.83\leq X\leq a)=\int\limits^{a}_{1.83} {\frac{1}{33}} \, dx \\\\0.31=\frac{1}{33}\cdot \int\limits^{a}_{1.83} {1} \, dx \\\\0.31\times 33=[x]^{a}_{1.83}\\\\10.23=a-1.83\\\\a=10.23+1.83\\\\a=12.06$

Thus, the value of <em>a</em> is 12.06.

7 0

4 years ago

Can someone please help me?

NARA [144]

Answer:

512

Step-by-step explanation:

5 0

3 years ago

How do I divide 5.6<br><br>

tekilochka [14]

Answer: you can divide it by 2 and get 2.8 or you can divide it by 8 and get .7 or do 5.6 divided by 7 and get .8 ( I don’t really know what your asking but here you go )

3 0

3 years ago

Misty and Yesenia have a group of base ten blocks. Misty has six more blocks than yesenia. usinas blocks represent 17. together

Anarel [89]

Answer : Misty has 14 blocks and Yesenia has 8 blocks.

Value of each block will be 68 and 25 respectively.

Explanation :

Since we have given that

Let Number of blocks Yesenia has be x

Let Number of blocks Misty has be x+6

According to question,

$x+x+6=22\\\\2x+6=22\\\\2x=22-6\\\\2x=16\\\\x=\frac{16}{2}\\\\x=8$

So, Number of blocks Misty has =x+6=8+6=14

and

Number of blocks Yesenia has =x=8

Now, Yesenia blocks represent 17 ie.e

8 blocks represent 17

Similarly,

22 blocks represent 85

So, According to question,

Remaining blocks = 22-8=14 which represent remaining value i.e. 85-17=68

So, 14 blocks represents 68, which is the value of it.

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4 years ago