Answer:
Step-by-step explanation:
<u>According to the graph, the line has the following intercepts.</u>
- y - intercept of (0, - 3)
- x - intercept of (6, 0)
<u>The line equation is:</u>
<u>The slope is:</u>
- m = (0 - (-3)) / (6 - 0) = 3/6 = 1/2
<u>The line is:</u>
5/7, I don't know what that is as a decimal, but I hope it helps
You have to estimate the slope of the tangent line to the graph at <em>t</em> = 10 s. To do that, you can use points on the graph very close to <em>t</em> = 10 s, essentially applying the mean value theorem.
The MVT says that for some time <em>t</em> between two fixed instances <em>a</em> and <em>b</em>, one can guarantee that the slope of the secant line through (<em>a</em>, <em>v(a)</em> ) and (<em>b</em>, <em>v(b)</em> ) is equal to the slope of the tangent line through <em>t</em>. In this case, this would be saying that the <em>instantaneous</em> acceleration at <em>t</em> = 10 s is approximately equal to the <em>average</em> acceleration over some interval surrounding <em>t</em> = 10 s. The smaller the interval, the better the approximation.
For instance, the plot suggests that the velocity at <em>t</em> = 9 s is nearly 45 m/s, while the velocity at <em>t</em> = 11 s is nearly 47 m/s. Then the average acceleration over this interval is
(47 m/s - 45 m/s) / (11 s - 9 s) = (2 m/s) / (2 s) = 1 m/s²
Answer:
You didn't give any statements so I'll tell you that it's a vertical line.
Step-by-step explanation:
The area of the rectangle is length times width, that is
A = L*W
The problem requires the width so
W = A/L
Given that A = 437 sq. cm and L = 19 cm, therefore
W = 437/19 = 23 cm
That is the answer.
