If X is between P and Q, then PQ is the whole line segment and XQ and XP are line segments that add up to PQ. Therefore, you can make an equation where XQ and XP add up to PQ.
XQ + XP = PQ
(3k) + (7k - 2) = 6k + 18
Combine like terms.
10k - 2 = 6k + 18
Add 2 to both sides.
10k = 6k + 20
Subtract 6k from both sides.
4k = 20
Divide both sides by 4.
k = 5
Plug 5 for k into XP.
XP = 7(5) - 2 ⇒ 35 - 2
XP = 33
If we are to choose any number from 100 to 500, you may take any other number but for the purpose of showing how things are done here, let me choose 100 gallons. Similarly, we choose 2 gallons to be drain out each day.
The equation that would best represent the relationship between the given parameters is,
y = 100 - 2x
where y is the volume of water after x days.
Solve for x in X-2 (x=8)
Substitute X=8 into 3x - 6y =18 (24-6y=18)
Solve for y in 24-6y=18 (y=1)
X=8 and y=1
Answer:
its a right angle and the area of it is 24
Step-by-step explanation: