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muminat
3 years ago
15

ennifer buys a new typewriter for $590. Jennifer puts 20% down and will pay $70 a month for the next 10 months. What's the total

amount of monthly payments?
Mathematics
1 answer:
VMariaS [17]3 years ago
8 0
The total amount paid in monthly payments is found by multiplying $70 by 10.  This is the only information that is needed to find the amount paid over 10 months.

70 x 10 = $700

Ennifer will pay $700 in monthly payments.
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Given sin x=13/85 and tan x=13/84 .
olga55 [171]

ANSWER:

We know that,

  • tanΘ = sinΘ/cosΘ

cosΘ = sinΘ/tanΘ

So, cosΘ = 13/85 ÷ 13/84

  • 13/85 × 84/13
  • 84/85.
7 0
3 years ago
Please help! Explain how to solve!
Gnesinka [82]
So this one is a little tricky because in order to solve you need to combine like terms. The only problem is that two fractions don't have the same denominator.
This is what you do.
2/3 - 1/9
= (2*9) - (1*3) / 3*9
= 18 - 3 / 27
= 15/ 27
Simplify.
5/9 + y = 7/9
Now since you need to isolate the variable you have to subtract 5/9 from both sides. Since the denominator is the same you can just subtract the numerator. 
So y = 2/9
I hope this helps love! :)
3 0
3 years ago
Please help
Mnenie [13.5K]

<u>Given</u>:

Given that the radius of the sphere is 9 cm

We need to determine the volume of the sphere.

<u>Volume of the sphere:</u>

Let us determine the volume of the sphere.

The volume of the sphere can be determined using the formula,

V=\frac{4}{3} \pi r^3

where r is the radius of the sphere.

Substituting r = 9 in the above formula, we get;

V=\frac{4}{3} \pi (9)^3

V=\frac{4}{3} \pi (729)

V=\frac{2916}{3} \pi

V=972 \pi

Thus, the volume of the sphere is 972π cm³

Hence, Option B is the correct answer.

7 0
3 years ago
Suppose that – in any given time period – a certain stock is equally likely to go up 1 unit or down 1 unit, and that the outcome
Scorpion4ik [409]

Answer:

Step-by-step explanation:

From the given information:

Let X represent the amount of the stock that goes up in the first period; &

Let Y denote the cumulative amount that goes up in the first three periods.

Then,

X= X_1 + X_2 \\ \\ \\EX=  EX_1 +EX_2\\ \\\\Now ; EX = 0 \\ \\ EX = \dfrac{1}{2}\times 1 + \dfrac{1}{2}\times -1 \\ \\ EX = \dfrac{1}{2}-\dfrac{1}{2} \\ \\ EX = 0

Cov(x,y) = Var(X_1) +Var(X_2) \\ \\ =\dfrac{1}{2}(1+1) + \dfrac{1}{2}(1+1) \\ \\ = \dfrac{1}{2}(2)+ \dfrac{1}{2}(2)  \\ \\ = 1+1  \\ \\ =2

Var (X) = Var (X_1+X_2)\\ \\ = 2 \ Var(X_1)  \\ \\ = 2 \times (1) \\ \\  = 2

Var (Y) = Var (X_1 +X_2+X_3) \\ \\ = 3 \times Var(X_1) = \\ \\ = 3 \times 1\\   \\ = 3

∴

Corr(x,y) = \dfrac{2}{\sqrt{6}} \\ \\ = \dfrac{2}{\sqrt{2\times 3}} \\ \\= \sqrt{\dfrac{2}{3}}

3 0
2 years ago
The sum of the first number cubed and the second number is 500 and the product is a maximum.
soldier1979 [14.2K]

We are given the following information:

the sum of the first number cubed and the second number is 500

their product is a maximum

We are looking for the 2 missing numbers.

To answer this, let's represent the two numbers as x and w.

From the given, we can form the following equation:

x^3+w=500

We can then express y as:

w=500-x^3

We can express their product as:

x(500-x^3)=500x-x^4

To find the maximum value of x, let's solve for the derivative of -x^4 + 500 x.

\begin{gathered} f(x)=-x^4+500x \\ f^{\prime}(x)=-4x^3+500 \end{gathered}

Then we solve for the value of x where f'(x) = 0.

\begin{gathered} -4x^3+500=0 \\ -4x^3=-500 \\ x^3=125 \\ x=5 \end{gathered}

Then we use x = 5 to solve for the second number, w.

\begin{gathered} w=500-x^3 \\ w=500-5^3 \\ w=500-125 \\ w=375 \end{gathered}

Therefore, the two numbers are 5 and 375.

3 0
1 year ago
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