So focusing on x^4 + 5x^2 - 36, we will be completing the square. Firstly, what two terms have a product of -36x^4 and a sum of 5x^2? That would be 9x^2 and -4x^2. Replace 5x^2 with 9x^2 - 4x^2:
Next, factor x^4 + 9x^2 and -4x^2 - 36 separately. Make sure that they have the same quantity inside of the parentheses:
Now you can rewrite this as , however this is not completely factored. With (x^2 - 4), we are using the difference of squares, which is . Applying that here, we have . x^4 + 5x^2 - 36 is completely factored.
Next, focusing now on 2x^2 + 9x - 5, we will also be completing the square. What two terms have a product of -10x^2 and a sum of 9x? That would be 10x and -x. Replace 9x with 10x - x:
Next, factor 2x^2 + 10x and -x - 5 separately. Make sure that they have the same quantity on the inside:
Now you can rewrite the equation as . 2x^2 + 9x - 5 is completely factored.
<h3><u>Putting it all together, your factored expression is
</u></h3>
Answer:
yes
Step-by-step explanation:
Answer:
see below
Step-by-step explanation:
To check your solution , plug the value of k into the original equation
6(7k-10) =24
k=2
6(7*2-10) =24
6(14-10) =24
6(4) =24
24=24
The solution is correct
3x-4y=12
4y=3x-12
y=(3x-12)/4
y=(3/4)x-3