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prisoha [69]
2 years ago
13

John bought 3 bottles of an energy drink for $4.50. Write an equation relating the total cost y to the number of energy drinks b

ought x. *
Mathematics
1 answer:
Nataly [62]2 years ago
6 0

Answer:

Step-by-step explanation:

y = 3 times x

or: y divided by x = 3

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What is the m∠2 if m∠4 = 81° and m∠3 = 40°?<br> a. 40°<br> b. 59°<br> c. 41° <br> d. 60°
velikii [3]

Answer:

C. 41

Step-by-step explanation:

180 - 81 = 99

99+40 = 139

180 -139 = 41

8 0
3 years ago
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Use the relationships between the angles to find the value of x (please answer)
Varvara68 [4.7K]

Step-by-step explanation:

x + 15 \degree = 102 \degree \:  \\ (corresponding \:  \angle s) \\  \therefore \: x =  102 \degree -  15 \degree  \\  \huge \red { \boxed{\therefore \: x =  87 \degree}}

4 0
3 years ago
In the illustration below, the three cube-shaped tanks are identical. The spheres in any given tank
fredd [130]

Answer:

1) Volume occupied by the spheres are equal therefore the three tanks contains the same volume of water

2) Amount \ of \, water \ remaining \ in \, the \ tank \ is \  \frac{x^3(6-\pi) }{6}

Step-by-step explanation:

1) Here we have;

First tank A

Volume of tank = x³

The  volume of the sphere = \frac{4}{3} \pi r^3

However, the diameter of the sphere = x therefore;

r = x/2 and the volume of the sphere is thus;

volume of the sphere = \frac{4}{3} \pi \frac{x^3}{8}= \frac{1}{6} \pi x^3

For tank B

Volume of tank = x³

The  volume of the spheres = 8 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 2·D = x therefore;

r = x/4 and the volume of the sphere is thus;

volume of the spheres = 8 \times \frac{4}{3} \pi (\frac{x}{4})^3= \frac{x^3 \times \pi }{6}

For tank C

Volume of tank = x³

The  volume of the spheres = 64 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 4·D = x therefore;

r = x/8 and the volume of the sphere is thus;

volume of the spheres = 64 \times \frac{4}{3} \pi (\frac{x}{8})^3= \frac{x^3 \times \pi }{6}

Volume occupied by the spheres are equal therefore the three tanks contains the same volume of water

2) For the 4th tank, we have;

number of spheres on side of the tank, n is given thus;

n³ = 512

∴ n = ∛512 = 8

Hence we have;

Volume of tank = x³

The  volume of the spheres = 512 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 8·D = x therefore;

r = x/16 and the volume of the sphere is thus;

volume of the spheres = 512\times \frac{4}{3} \pi (\frac{x}{16})^3= \frac{x^3 \times \pi }{6}

Amount of water remaining in the tank is given by the following expression;

Amount of water remaining in the tank = Volume of tank - volume of spheres

Amount of water remaining in the tank = x^3 - \frac{x^3 \times \pi }{6} = \frac{x^3(6-\pi) }{6}

Amount \ of \ water \, remaining \, in \, the \ tank =  \frac{x^3(6-\pi) }{6}.

5 0
3 years ago
Y=-1/9x-4 Which of the following is the equation of a line that is parallel?
fenix001 [56]

Any line with a slope of -1/9 will be parallel

4 0
2 years ago
What is the product of −3/11 and <br> −2/15?
Dafna11 [192]
Multiply -3/11 and -2/15 straight across

-3(-2) = 6
11(15) = 165

6/165 is your product, or 0.036 (rounded)


hope this helps
5 0
3 years ago
Read 2 more answers
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